Answer:
K = ρL²g
Explanation:
Consider L as the length of the raft inside the water when the raft is displaced through additional distance y;
Then:
F = upthrust ( restoring force) = weight of the liquid displaced.
where;
A = L²
F = ky.
Then,
Divide both sides by y
K = ρL²g
<span>Objective Lenses: Usually you will find 3 or 4 objective lenses on a microscope. They almost always consist of 4X, 10X, 40X and 100X powers. When coupled with a10X (most common) eyepiece lens, we get total magnifications of 40X (4X times10X), 100X , 400X and 1000X.</span>
Answer:
μ = 0.0315
Explanation:
Since the car moves on a horizontal surface, if we sum forces equal to zero on the Y-axis, we can determine the value of the normal force exerted by the ground on the vehicle. This force is equal to the weight of the cart (product of its mass by gravity)
N = m*g (1)
The friction force is equal to the product of the normal force by the coefficient of friction.
F = μ*N (2)
This way replacing 1 in 2, we have:
F = μ*m*g (2)
Using the theorem of work and energy, which tells us that the sum of the potential and kinetic energies and the work done on a body is equal to the final kinetic energy of the body. We can determine an equation that relates the frictional force to the initial speed of the carriage, so we will determine the coefficient of friction.
where:
vf = final velocity = 0
vi = initial velocity = 85 [km/h] = 23.61 [m/s]
d = displacement = 900 [m]
F = friction force [N]
The final velocity is zero since when the vehicle has traveled 900 meters its velocity is zero.
Now replacing:
(1/2)*m*(23.61)^2 = μ*m*g*d
0.5*(23.61)^2 = μ*9,81*900
μ = 0.0315
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The amount of heat required for the sublimation of 40.0 g of solid dry ice CO₂ is <u>29.3 kJ.</u>
One mole of CO₂ has a mass of 44.0095 g.
Calculate the number of moles n in 40.0 g of CO₂ .
Heat of sublimation is the amount of heat required by 1 mole of a substance to convert itself from solid state to a vapor state at constant temperature and pressure.
1 mole of CO₂ requires 32.3 kJ of energy to sublimate.
Therefore, the heat required to sublimate 0.9089 mol of CO₂ is given by,
Thus, the heat required to sublimate 40.0 g of CO₂ is <u>29.3 kJ</u>.