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Marrrta [24]
1 year ago
11

Jane has gone on a diet.She starts with weight of 61kg and loses 2kg every 3 weeks for 12 weeks.she abandoned her diet at the st

art of a 2 week holiday, and gains back 1kg per week.How much does she weigh at the end of her holiday?​
Mathematics
1 answer:
andrezito [222]1 year ago
7 0

Answer:

55 kg

Step-by-step explanation:

lose 2kg per 3 week

for 12 weeks

3×4=12

4×2=8

61-8=53

1kg per week gained for 2 weeks = 2kg

53kg + 2 kg =55kg

Hope you understand...

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forsale [732]

Answer: c. 22X

Step-by-step explanation:

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3 years ago
Please help me ASAP!!
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The answer is D, i.e. the system was solved via elimination


If you multiply the first equation by 5, the system becomes


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If you sum the two equations, you get


-16y = 32


And so if you substitute the second equation of system A with this new equation, you'll get system B.

3 0
2 years ago
A number is first increased by 20 and then doubled. The result is 2 less than 5 times
Iteru [2.4K]

i  think maybe ? x+20*2=5-2*x

8 0
2 years ago
An elevator containing five people can stop at any of seven floors. What is the probability that no two people exit at the same
elena-s [515]

Answer:

Approximately 0.15 (360 / 2401.) (Assume that the choices of the 5 passengers are independent. Also assume that the probability that a passenger chooses a particular floor is the same for all 7 floors.)

Step-by-step explanation:

If there is no requirement that no two passengers exit at the same floor, each of these 5 passenger could choose from any one of the 7 floors. There would be a total of 7 \times 7 \times 7 \times 7 \times 7 = 7^{5} unique ways for these 5\! passengers to exit the elevator.

Assume that no two passengers are allowed to exit at the same floor.

The first passenger could choose from any of the 7 floors.

However, the second passenger would not be able to choose the same floor as the first passenger. Thus, the second passenger would have to choose from only (7 - 1) = 6 floors.

Likewise, the third passenger would have to choose from only (7 - 2) = 5 floors.

Thus, under the requirement that no two passenger could exit at the same floor, there would be only (7 \times 6 \times 5 \times 4 \times 3) unique ways for these two passengers to exit the elevator.

By the assumption that the choices of the passengers are independent and uniform across the 7 floors. Each of these 7^{5} combinations would be equally likely.

Thus, the probability that the chosen combination satisfies the requirements (no two passengers exit at the same floor) would be:

\begin{aligned}\frac{(7 \times 6 \times 5 \times 4 \times 3)}{7^{5}} \approx 0.15\end{aligned}.

5 0
2 years ago
If angle LMPis 11 degrees more than angle NMP and angle NML is 137 find each measure.
OLEGan [10]

Answer:

angle NMP = 63°

angle LMP = 74°

Step-by-step explanation:

Let angle NMP be x° . It's given that angle LMP is 11° more than angle NMP. So, angle LMP = x° + 11°

But angle NML = 137°.

So,

angle NMP + angle LMP = 137°

=> x° + x° + 11° = 137°

=> 2x° + 11° = 137°

=> 2x° = 137° - 11°

= 126°

=> x° = 126/2 = 63°

angle NMP = 63°

angle LMP = 63 + 11 = 74°

7 0
3 years ago
Read 2 more answers
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