Answer:
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To solve this, you’ll first need to solve for their slopes.
The slope for line Q is y2-y1/x2-x1 = -8-(-2)/-8-(-10) = -3
We know that the lines are perpendicular so the negative reciprocal of -3 is 1/3
The equation you get it y = 1/3x + b.
Now you will need to solve for b by substituting in the first ordered pair of line R.
2 = 1/3(1) + b.
Once you solve for b, you should get 5/3 and y = 1/3x + 5/3
Now, to find a, you will need to substitute in 10 from the second ordered pair into x in your new equation.
y = 1/3(10) + 5/3.
Your solution should be 5.
So your answer is: a = 5
Answer:
Yea it does
Step-by-step explanation:
The answer is :
4b+7
hope this helps!!
ET is tangent to circle A so ET is perpendicular to AT
So <ATE = 90°
Given <TNG = 35°
<NET = <ATE - <TNG
= 90° - 35°
= 55°
Answer is 55°
