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Olegator [25]
2 years ago
6

Find the domain of f(x)=sec(2x)

Mathematics
1 answer:
rjkz [21]2 years ago
6 0

Answer:

*Refer the image attached

Step-by-step explanation:

*Refer the image attached

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Show that the relation R consisting of all pairs(x, y)such that x and y are bit strings of length three or more that agree in th
Mice21 [21]

Answer:

See proof below

Step-by-step explanation:

An equivalence relation R satisfies

  • Reflexivity: for all x on the underlying set in which R is defined, (x,x)∈R, or xRx.
  • Symmetry: For all x,y, if xRy then yRx.
  • Transitivity: For all x,y,z, If xRy and yRz then xRz.

Let's check these properties: Let x,y,z be bit strings of length three or more

The first 3 bits of x are, of course, the same 3 bits of x, hence xRx.

If xRy, then then the 1st, 2nd and 3rd bits of x are the 1st, 2nd and 3rd bits of y respectively. Then y agrees with x on its first third bits (by symmetry of equality), hence yRx.

If xRy and yRz, x agrees with y on its first 3 bits and y agrees with z in its first 3 bits. Therefore x agrees with z in its first 3 bits (by transitivity of equality), hence xRz.

5 0
3 years ago
What is the simplified form of the following expression 7(^3√2x)-3(^3√16x)-3(^3√8x)
svlad2 [7]

Answer:

The simplified form of the expression is \sqrt[3]{2x}-6\sqrt[3]{x}

Step-by-step explanation:

Given : Expression 7\sqrt[3]{2x}-3\sqrt[3]{16x}-3\sqrt[3]{8x}

To Simplified : The expression

Solution :  

Step 1 - Write the expression

7\sqrt[3]{2x}-3\sqrt[3]{16x}-3\sqrt[3]{8x}

Step 2- Simplify the roots and re-write as

16=2^3\times2 and 8=2^3

7\sqrt[3]{2x}-3\times2\sqrt[3]{2x}-3\times2\sqrt[3]{x}

Step 3- Solve the multiplication

7\sqrt[3]{2x}-6\sqrt[3]{2x}-6\sqrt[3]{x}

Step 4- Taking \sqrt[3]{2x} common from first two terms

\sqrt[3]{2x}(7-6)-6\sqrt[3]{x}

\sqrt[3]{2x}-6\sqrt[3]{x}

Therefore, The simplified form of the expression is \sqrt[3]{2x}-6\sqrt[3]{x}

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