To subtract fractions, we need a common denominator.

-

the common denominator will be (y-2)(y+3)



The answer above will be the simplified form.
Answer:
The values of k are 2/3 and -1
Step-by-step explanation:
Product of zeros = αβ= constant / coefficient of x^2 = 4/k
Sum of zeros =α+β = - coefficient of x / coefficient of x^2= -4/k
Given
Consider a= α and b= β

can be written as
if we add
in the above equation.


Putting values of αβ and α+β

The values of k are 2/3 and -1