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2 years ago

Math PT Question 19 Which of the following is the correct equation for the trend line in the scatter plot ?

Mathematics

2 answers:

ki77a [65]2 years ago

8 0

Using the points where the blue line crosses the X and Y axis:

(0,5) ans (-1, 0)

The slope is the change in Y over the change in X:

0-5 / -1 - 0 = -5/-1 = 5

Slope = 5

Y intercept = y1 = 5

Equation = y = 5x+5

Tema [17]2 years ago

5 0

Answer:

The correct equation for the trend line is y = 5x + 5

Step-by-step explanation:

* Lets revise the form of the equation of the line

- The slope intercept form is y = mx + b, where m is the slope of

the line and b is the y-intercept

- In the problem we have a trend line in the scatter-plot

- we cant find the exact value of the slope of the line from the points

in the scatter-plot because the line is best fit to the point, then we

will start with the y-intercept of the line

- From the graph the line intersect the y-axis at point (0 , 5)

∴ The y-intercept is 5

- We have two answers have y- intercept = 5, the first and second

answer, the right answer is one of them

- From the graph try to find two points closed the the line and use

them to find the slope of the line

- There are two points approximately closed to the line at points

(0 , 5) and (-1 , 0)

- Lets use the rule of the slope of a line which passes through points

(x1 , y1) and (x2 , y2)

- The slope of the line = (y2 - y1)/(x2 - x1)

∵ The point (0 , 5) is (x1 , y1) and point (-1 , 0) is (x2 , y2)

∵ x1 = 0 , x2 = -1 and y1 = 5 , y2 = 0

∴ the slope = (0 - 5)/-1 - 0 = -5/-1 = 5

∵ The equation of the line is y = mx + b

∵ m = 5 and b = 5

∴ The equation is y = 5x + 5

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Simply add up all.

4 1/2 + 6 2/3 + 9 1/4

(4 + 6 + 9) + 1/2 + 2/3 + 1/4

19 6/12 + 8/12 + 3/12 = (6+8+3)/12 = 17/12

19 17/12

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19 + 1 5/12

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20 5/12 yards was purchased.

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3 years ago

Read 2 more answers

Z+x3:use x = 1 and z = 19

pogonyaev

Answer:21

Step-by-step explanation: plug in 19 and 1

1x3 is 3 plus 19 is 21

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3 years ago

Find the area of following figure...?

MrRa [10]

Answer:

33600 m²

Step-by-step explanation:

The top and bottom horizontal sides are parallel, so this is a trapezoid with bases DC and AB. The height is BC.

area of trapezoid = (a + b)h/2

where a and b are the lengths of the bases, and h is the height.

We need to find the height, BC.

Drop a perpendicular from point A to segment DC. Call the point of intersection E. E is a point on segment DC.

DE + EC = DC

EC = AB = 360 m

DC = 600 m

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DE = 240 m

Use right triangle ADE to find AE. Then BC = AE.

DE² + AE² = AD²

DE² + 240² = 250²

DE² = 62500 - 57600

DE² = 4900

DE = √4900

DE = 70

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1 year ago

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Solve the following initial-value problem: (ex+y)dx+(3+x+yey)dy=0, y(0)=1 0=

alex41 [277]

Answer:

$e^x+xy+3y+(y-1)e^y=4$

Step-by-step explanation:

Given that

$(e^x+y)dx+(3+x+ye^y)dy=0$

Here

$M=e^x+y$

$N=3+x+ye^y$

We know that

M dx + N dy=0 will be exact if

$\frac{\partial M}{\partial y}=\frac{\partial N}{\partial x}$

$\frac{\partial M}{\partial y}=1$

$\frac{\partial N}{\partial x}=1$

it means that this is a exact equation.

$\int d\left(e^x+xy+3y+(y-1)e^y\right)=0$

Noe by integrating above equation

$e^x+xy+3y+(y-1)e^y=C$

Given that

x= 0 then y= 1

$e^0+0+3+(1-1)e^1=C$

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So the our final equation will be

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3 years ago

If you lived in a hobbit house and had a round window that needed? trim, how much trim would be needed to go around a window wit

katen-ka-za [31]

Answer:

To find out how much trim you would need for the window, you would need to calculate the Circumference.

Step-by-step explanation:

Circumference is the length around a circle and is calculated using the following formula.

$C = 2\pi r$

In which C is the circumference and r is the radius. Since we already know the radius all we have to do is plug it into the equation and solve for C.

$C = 2\pi (4.2)$

$C = 26.389 ft$

Answer: The window has a Circumference of 26.389 feet so you would need that amount of trim to fit the area around the window.

Hope my answer would be a great help for you.

If you have more questions feel free to ask here at Brainly.

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