Let
x------> hours worked by Sara last week
y------> hours worked by Joan last week
z------> hours worked by Erin last week
we know that
x=28 hours ------> equation 1
y=x-6-----> equation 2
substitute the value of x in equation 2
y=28-6=22 hours
z=y/2------> equation 3
substitute the value of y in the equation 3
z=22/2=11 hours
<u>the answer is</u>
Sara worked 28 hours last week
Joan worked 22 hours last week
Erin worked 11 hours last week
Domain of a Function is a Set of Values under which the Function is defined or a Set of Values which satisfy the respective Function.
From the Diagram we can Notice that the Function is Defined only with the Values : (-6 , -1] ∪ (1 , 5]
⇒ Domain of the Given Function is (-6 , -1] ∪ (1 , 5]
Range is the Set of Values which we get under the Defined values of Domain of the Given Function.
From the Diagram we can Notice that the Values of the Given Function under the Defined Domain range from : (-3 , 2] ∪ [3 , 7)
⇒ Range of the Given Function is (-3 , 2] ∪ [3 , 7)
2nd Option is the Answer
The gardeners should buy 54 white hydrangeas and 88 pink hydrangeas altogether.
Step-by-step explanation:
Let,
Number of white hydrangeas = x
Number of pink hydrangeas = y
According to given statement;
In first bed
x+y = 40 Eqn 1
In second bed
2 times the number of white hydrangeas and 3 times the number of pink hydrangeas as in the first bed.
2x+3y=102 Eqn 2
Multiplying Eqn 1 by 2
Subtracting Eqn 3 from Eqn 2
Putting y=22 in Eqn 1
Number of white hydrangeas altogether = x+2x = 3x = 3(18) = 54
Number of pink hydrangeas altogether = y+3y = 4y = 4(22) = 88
The gardeners should buy 54 white hydrangeas and 88 pink hydrangeas altogether.
Keywords: linear equation, elimination method
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Answer:
7%
Step-by-step explanation: