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3 years ago

You move left 5 units and down 2 units.you end at (-4,-5).where did you start?

Mathematics

1 answer:

viktelen [127]3 years ago

6 0

Your answer I think would be You start at (5,-3)

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On a number line what is the distance between-3/7 and -2/3

Nikitich [7]

Is simply their difference,

$\bf -\cfrac{3}{7}-\left( -\cfrac{2}{3} \right)\implies -\cfrac{3}{7}+\cfrac{2}{3}\impliedby \textit{LCD of 21}\implies \cfrac{-3(3)+2(7)}{21}
\\\\\\
\cfrac{-9+14}{21}\implies \cfrac{5}{21}$

4 0

3 years ago

What percentage of 70 is 49?<br> Your answer

sweet-ann [11.9K]

the answer to your question is 70%. 49 is 70% of 70

3 0

2 years ago

ABCD is a parallelogram. What is the measure of ∠ACD?

Igoryamba

Step-by-step explanation:

Here

5x+16+7x-3+6x+5 = 180(being sum of triangle)

or, 18x=180-18

or, x= 162/18

so, x = 9

now,

here,

<ACD = <ACB(diagonals of parallelogram bisect eachother)

or, <ACD = 7x-3

or, <ACD = 7×9-3

or, <ACD = 63-3

So, <ACD = 60°

8 0

2 years ago

Given the figure below, find the values of x and z.<br> (10x - 65)<br> (9x - 49)

nexus9112 [7]

(10x - 65) degrees is equal to (9x - 49) degrees, therefore you can set them into an equation.

(10x - 65) = (9x - 49)

By subtracting 9x in both sides,

(10x - 9x) - 65 = (9x -9x) - 49

x - 65 = -49

By adding 65 in both sides,

x - 65 + 65= -49 + 65
x = 16

Next, to find the value of z, it’s important to know that the straight line has 180 degrees. Then you would substitute the x value you found into one of your equation and subtract it from 180.

10 (16) - 65 = 160 - 65 = 95

Now you know that (10x - 65) degrees is equal to 95 degrees,

180 - 95 = z = 85

Answer: x = 16
z = 85

5 0

2 years ago

A university researcher wants to estimate the mean number of novels that seniors read during their time in college. An exit surv

lys-0071 [83]

Answer:

Population mean = 7 ± 2.306 × $\frac{2.29}{\sqrt{9} }$

Step-by-step explanation:

Given - A university researcher wants to estimate the mean number

of novels that seniors read during their time in college. An exit

survey was conducted with a random sample of 9 seniors. The

sample mean was 7 novels with standard deviation 2.29 novels.

To find - Assuming that all conditions for conducting inference have

been met, which of the following is a 94.645% confidence

interval for the population mean number of novels read by

all seniors?

Proof -

Given that,

Mean ,x⁻ = 7

Standard deviation, s = 2.29

Size, n = 9

Now,

Degrees of freedom = df

= n - 1

= 9 - 1

= 8

⇒Degrees of freedom = 8

Now,

At 94.645% confidence level

α = 1 - 94.645%

=1 - 0.94645

=0.05355 ≈ 0.05

⇒α = 0.5

Now,

$\frac{\alpha}{2} = \frac{0.05}{2}$

= 0.025

Then,

$t_{\frac{\alpha}{2}, df }$ = 2.306

∴ we get

Population mean = x⁻ ± $t_{\frac{\alpha}{2}, df }$ × $\frac{s}{\sqrt{n} }$

= 7 ± 2.306 × $\frac{2.29}{\sqrt{9} }$

⇒Population mean = 7 ± 2.306 × $\frac{2.29}{\sqrt{9} }$

3 0

3 years ago

Read 2 more answers