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1 year ago

Solve for c -40= -5c — 25

Mathematics

1 answer:

Vikki [24]1 year ago

8 0

Answer:

c = 3

Step-by-step explanation:

Let's solve the problem,

→ -40 = -5c - 25

→ -5c = -40 + 25

→ -5c = -15

→ c = -15/-5

→ [ c = 3 ]

Hence, the value of c is 3.

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10.) Kelly is flying a kite to which the angle of elevation is

jarptica [38.1K]

Answer:

61.08m

Step-by-step explanation:

Let " l " be the length of the rope and " θ " the angle at which it is raised. In other words:

l = 65m
θ = 70°

As you can see, there has been made a right angle triangle. So:

$sin70 = \frac{h}{l} \\ h = l \times sin70 \\ h = 65 \times 0.9397 = 61.08 \\ h = 61.08$

So the kite is approximately 61.08m above the ground.

In order to find the sin70° i used a calculator.

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3 years ago

6×?×3=90 what's supposed to go in the ? Slot

bonufazy [111]

Answer:

Step-by-step explanation:

6 x 3 = 18

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3 years ago

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On the coordinate grid of a map, Josie's house is located at (2,7). Her school is located at (-5,5). If each map unit equals one

oksian1 [2.3K]

To find the distance you would use the distance formula which is:
$d = \sqrt{(x2-x1)^{2}+(y2-y1)^{2}} = \sqrt{(2-(-5))^{2}+(7-5)^{2}}$

This equals:
$d = \sqrt{(7)^{2}+(2)^2} = \sqrt{49+4} = \sqrt{53} = 7.2801$

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3 years ago

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Find the coordinates of G if F(2,5) is the midpoint of line GJ and J and has coordinates (-2,8)

dimulka [17.4K]

Answer:

G(6,2)

Step-by-step explanation:

If point $F(x_F,y_F)$ is the midpoint of the segment GJ, where $G(x_G,y_G)$ and $J(x_J,y_J)$ , then

$x_F=\dfrac{x_G+x_J}{2},\\ \\y_F=\dfrac{y_G+y_J}{2}.$

In your case,

$F(2,5),\ J(-2,8),$

therefore,

$2=\dfrac{x_G+(-2)}{2},\\ \\5=\dfrac{y_G+8}{2}.$

Thus,

$x_G-2=4\Rightarrow x_G=6,\\ \\y_G+8=10\Rightarrow y_G=2.$

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3 years ago

Please help 11 points up for grabs need full working out

RUDIKE [14]

The answer is 29.476, 29.4 degrees is your answer

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3 years ago

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