Consider the line (d) with equation y = –2x+6
1 answer:
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Answer:
Given:
n = 550
Po = 51% = 0.51
P0 - 1 = 0.51 - 1 = 0.49
p' = = 0.5218
np0(1 - p0) = 550*0.51(1-0.51)
= 137.4 ≥ 100
This means the sample size is greater than 5% of the population size. and the sample can be reasonably assumed to be random, the requirement for testing hypothesis are satisfied.
1) The null and alternative hypotheses:
H0 : p0 = 0.51
H1 : p0 ≠ 0.51
The test statistic Z,
Z = 0.55
This is two tailed test.
The pvalue for Z =0.55
Pvalue = 0.5824
3) Decision:
Since pvalue, 0.5824 is greater than significance level, we fail to reject null hypothesis H0.
Conclusion:
Do not reject Upper H0. There is not sufficient evidence at the alpha equals 0.01 level of significance to conclude that the proportion of females who are living alone has changed.
Answer:
B. Yes, there are at least 10 people with weak bones and 10 people with strong bones in each group.
Step-by-step explanation:
The Central Limit Theorem estabilishes that, for a random variable X, with mean and standard deviation
, a large sample size can be approximated to a normal distribution with mean
and standard deviation
The correct answer is:
B. Yes, there are at least 10 people with weak bones and 10 people with strong bones in each group.