Consider the diagram to the right below and complete the proof below

A factory has two types of employees line workers and Mananger

denis-greek [22]

Step-by-step explanation:

Read this article to learn about the types, functions, advantages and conflicts of line and staff organisation.

Types of Staff:

1. Personal Staff:

Personal staff is attached to individual line officers. The Personal Assistant or the Private Secretary etc. form personal staff of line managers. These persons help their bosses in every possible way. The routine work of line officers is mostly handled by the personal staff. They fix routine meetings, open the post, maintain diaries and accompany the boss on official visits. The line officers are spared of routine works and are able to devote much time for planning and execution.

2. Specialist Staff:

These are technically qualified persons who provide service to the whole organisation. They serve line and other staff in planning, organizing and coordinating their work. Their specialized knowledge is an asset to the organisation. The appointment of a legal advisor may be helpful to every department where his advice is required.

3. General Staff:

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This staff consists of persons attached to the key executives. They have the same background as that of line officers. They are attached to important functionaries as their deputies, etc. They may be appointed as Deputy Managers, Assistant Managers, Special Assistants, etc.

Functions of Staff Authority:

The staff authority is assigned the following functions:

1. Agency of Control:

It has to discharge the functions such as:

(a) Organisation;

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3 0

2 years ago

What is the equivalent to 28/42

grigory [225]

2/3, since those numbers can be divided by 14.

5 0

2 years ago

a circle has a center (3,5) and a diameter AB. The coordinates of A are (-4,6). what are the coordinates of B?

Kruka [31]

Find the length of the radius.

$r= \sqrt{(3-(-4))^2+(5-6)^2}
\\r = \sqrt{7^2+(-1)^2}
\\r= \sqrt{50} 
\\ r=5 \sqrt{2}$

Find the length of the diameter.

d = 2r = 2 × 5√2 = 10√2

Point B must lie on a line AC, where C is a center of a circle.
Find equation of line AC.
A(–4, 6), C(3, 5)

$y-y_1= \frac{y_2-y_1}{x_2-x_1}(x-x_1)
\\y-6= \frac{5-6}{3-(-4)} (x-(-4))
\\y-6=- \frac{1}{7} (x+4)
\\7y-42=-x-4
\\x+7y-38=0$

The distance from B(x, y) to C(3, 5) is 5√2.
$\sqrt{(x-3)^2+(y-5)^2}=5 \sqrt{2} 
 \\(x-3)^2+(y-5)^2=(5 \sqrt{2})^2 
\\(x-3)^2+(y-5)^2=50$

Solve system of equations.
$x+7y-38=0
\\(x-3)^2+(y-5)^2=50
\\
\\x=38-7y
\\(38-7y-3)^2+(y-5)^2=50
\\(35-7y)^2+(y-5)^2=50
\\1225-490y+49y^2+y^2-10y+25-50=0
\\50y^2-500y+1200=0
\\y^2-10y+24=0
\\y^2-6y-4y+24=0
\\y(y-6)-4(y-6)=0 \\(y-6)(y-4)=0 \\y_1=6,y_2=4
$

$x_1=38-7y_1=38-7 \times 6 = 38-42=-4
\\x_2=38-7y_2=38-7 \times 4 = 38-28=10
$

Point B could have coordinates
$\\
\\(x_1,y_1)=(-4,6),(x_2,y_2)=(10,4)
$

But (–4, 6) are the coordinates of point A.
Therefore, point B has coordinates (10,4).

8 0

3 years ago

Two boys decided to buy a computer. The second boy had 5 6 of the money the first had. The first boy had 7 8 of the price of the

sdas [7]

Answer: The price for the computer = $1152

Step-by-step explanation:

Let the first boy = F

Let the second boy = S

Let the price of computer = C

The second boy had 5/ 6 of the money the first had. I.e

S = 5/6 F

Then F = 6/5S ......(1)

The first boy had 7 /8 of the price of the computer. That is

F = 7/8C ....... (2)

Substitute F in (1) into (2)

6/5S = 7/8C

S = 5/6 × 7/8C

S = 35/48C ......(3)

Together they had $696.00 more than they need to pay. That is

F + S = C + 696 ........ (4)

Substitute equation 2 and 3 into 4

7/8C + 35/48C = C + 696

0.875C + 0.729C = C + 696

0.604C = 696

C = 696/0.604

C = 1152 dollars

Therefore, the price for the computer = $1152

7 0

2 years ago

Read 2 more answers

Please help !! Picture provided !!!

adelina 88 [10]

Method One
Your calculator might be able to do this. Mine does it like this.
6
nCr
2
=
15

Method 2
You could simply set up 6C2

This gives you
$\frac{n!}{(n- r)! r!} = \frac{6!}{(6 - 2)!2!} = \frac{6!}{4! 2!} = \frac{6*5}{2*1} = 15$

Method Three
You only have to do this a couple of times to see how the cancellation works.

$\frac{6!}{4!2!} = \frac{6*5*\st{4*3*2*1}}{4*3*2*1 * 2*1}$
After all the cancellation takes place you have
6*5/2 = 15

7 0

2 years ago