Draw structures from the following names, and determine which compounds are optically active:(b) 3-chloro-3-methylpentane
1 answer:
The given compound 3-chloro-3-methylpentane is not optically active .
Because this compound have plane of symmetry (POS) and center of symmetry (COS) i.e. have di-symmetry . And also forms superimposable mirror image . the compound is not optically active .
It does not have chiral center.
Here the carbon atom has only 3 distinct groups i.e. ethyl , chlorine , methyl .
<h3>What is di-symmetry?</h3>Di-symmetry is that which have no center of symmetry and plane of symmetry and alternate axis of symmetry .
<h3>Chiral center :</h3>Have Sp3 hybridized center (4sigma bond ) .
4 distinct group is attached to the chiral atom. form non -superimposable mirror image .
<h3>What is optical isomerism ?</h3>Same molecular formula and same structural formula . also have same physical and chemical properties .
They differ in their behavior towards plane polarized light (ppl) .
Learn more about chiral center here:
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