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lutik1710 [3]
2 years ago
8

Draw structures from the following names, and determine which compounds are optically active:(b) 3-chloro-3-methylpentane

Chemistry
1 answer:
VladimirAG [237]2 years ago
8 0

The given compound 3-chloro-3-methylpentane is not optically active .

Because this compound  have plane of symmetry (POS) and center  of symmetry (COS) i.e.  have di-symmetry . And also forms  superimposable mirror image . the compound is not optically active .

It does not have chiral center.

Here the carbon atom has only 3 distinct groups i.e. ethyl , chlorine ,  methyl .

<h3>What is di-symmetry?</h3>

Di-symmetry is that which have no center of symmetry and plane of symmetry and alternate axis of symmetry .

<h3>Chiral center :</h3>

Have Sp3 hybridized center (4sigma bond ) .

4 distinct group  is attached to the chiral atom. form non -superimposable mirror image .

<h3>What is optical isomerism ?</h3>

Same molecular formula and same structural formula . also have same physical and chemical properties .

They differ in their behavior towards plane polarized light (ppl) .

Learn more about chiral center here:

brainly.com/question/9522537

#SPJ4

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