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3 years ago

What is the driving force for the reaction of HCl(aq) and NaOH(aq)?

1 answer:

8 0

HCl and NaOH react based on the following equation:
HCl + NaOH ..............> NaCl + H2O

This reaction is known as a double replacement reaction. In this types of reactions, the electrolyte (and the solvent) is water and the driving force is mainly the formation of a non-electrolyte produce.

Based on this, the driving force in the above neutralization reaction is the formation if the non-electrolyte salt (NaCl)

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How many grams of oxygen is needed to completely react with 9.30 moles of aluminum

Orlov [11]

Balanced chemical equation:

* moles of oxygen

4 Al + 3 O2 = 2 Al2O3

4 moles Al -------------- 3 moles O2
9.30 moles Al ---------- moles O2

moles O2 = 9.30 * 3 / 4

moles O2 = 27.9 / 4 => 6.975 moles of O2

Therefore:

Molar mass O2 = 31.9988 g/mol

n = m / mm

6.975 = m / 31.9988

m = 6.975 * 31.9988

m = 223.19 of O2

5 0

3 years ago

5. The element copper has naturally occurring isotopes with mass numbers of 63

natali 33 [55]

Answer:

63.616

Explanation:

DATA

1. first atomic mass;m1=63

second atomic mass;m2=65
first percentage;p1= 69.2%
second percentage me;p2=30.8%
average mass;avg= ?

SOLUTION

avg= (m1)(p1) + (m2)(p2)

100

avg= (63)(69.2) + (65)(30.8)

100

avg= 4359.6 + 2002

100

avg= 6361.6

100

avg= 63.616

4 0

3 years ago

Read 2 more answers

A 9.86 g sample of an aqueous solution of hydroiodic acid contains an unknown amount of the acid. If 27.5 mL of 0.337 M potassiu

Aneli [31]

Answer:

88.3% of hydroiodic acid is found

7 0

3 years ago

What is the mass (grams) of salt in 10.0 m' of ocean water? ball park-4x10's (1.000 molsalt -58.44 g salt, 1.0 L ocean water -0.

koban [17]

Answer:

3.5 × 10⁵ g of salt

Explanation:

What is the mass (grams) of salt in 10.0 m³ of ocean water?

We have this data:

1.000 mol salt is equal to 58.44 g salt
1.0 L of ocean water contains 0.60 mol of salt

We will need the following relations:

1 L = 1dm³
1 m³ = 10³ dm³

We can use proportions:

$10.0m^{3} .\frac{10^{3}dm^{3} }{1m^{3} } .\frac{1L}{1dm^{3} } .\frac{0.60molSalt}{1.0L} .\frac{58.44gSalt}{1molSalt} =3.5 \times 10^{5} gSalt$

8 0

3 years ago

Given the following equation: 2 K + Cl2 ---> 2 KCl

Ksivusya [100]

Answer:

2 moles of KCl will be produced

Explanation:

Given parameters:

Number of moles of K = 2 moles

Unknown:

Number of moles of KCl produced = ?

Solution:

To solve this problem;

Obtain a balanced chemical equation:

2K + Cl₂ → 2KCl ;

Since K is the limiting reactant, its amount will determine the extent of this reaction.

From the balanced equation;

2 moles of K will produce 2 moles of KCl

Given that 2 moles of K reacted, 2 moles of KCl will be produced

5 0

3 years ago