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Anestetic [448]
3 years ago
9

https://Suppose that the concentration of CO2 available for the Calvin cycle decreased by 50% (because the stomata closed to con

serve water). Which statement correctly describes how O2 production would be affected? (Assume that the light intensity does not change.)/105793539/ch-10-flash-cards/ . A. The rate of O2 production would remain the same because light reactions are independant of Calvin Cycle B. The rate of O2 production would remain the same because the light intensity did not change. C. The rate of O2 production would decrease because the rate of ADP
Chemistry
1 answer:
Ipatiy [6.2K]3 years ago
5 0

Answer: C. The rate of O2 production would decrease because the rate of ADP and NADP+ production by the Calvin cycle would decrease

Explanation: It is true that the Calvin Cycle is not directly dependent on light, but it is indirectly dependent on light because the energy carriers (ATP and NADPH) are produced by light-dependent reactions. Carbon dioxide and two other components (ribulose bisphosphate carboxylase and three molecules of ribulose bisphosphate) are the ones to initiate the light-independent reactions. Thus, the concentration of CO2 will determine the rate of ADP and NADP+ production, which will directly affect the rate of production of O2.

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how many moles of carbon monoxide can be produced from 8 moles of carbon if carbon is the limiting reagent?
Mademuasel [1]

Answer:

8 moles of CO

Explanation:

To produce carbon monoxide we begin from C and O₂ as this reaction shows:

2C + O₂ → 2CO

Therefore, 2 moles of C can produce 2 moles of CO

If I have 8 moles of C, I must produce 8 moles of CO

Ratio is 1:1

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When octane (C8H18) is burned in the presence of oxygen, the yield of products (carbon dioxide and water) is 87%. What mass of c
ahrayia [7]

Answer:

14.5g of CO₂ are produced

Explanation:

The reaction of octane with oxygen is:

C₈H₁₈ + 25/2O₂ → 8CO₂ + 9H₂O

<em>Where 1 mole of octane (Molar mass: 114.23g/mol) reacts with 25/2 moles of O₂ (Molar mass 32g/mol) to produce 8 moles of CO₂ and 9 moles of water.</em>

When 21.0 g of octane is burned with 19.0 g of oxygen gas you need to find <em>limiting reactant </em>to find how many moles of products are formed:

Octane: 21.0g ₓ (1mol / 114.23g) = 0.184 moles octane

Oxygen: 19.0g ₓ (1 mol / 32g) = 0.594 moles oxygen

For a complete reaction of 0.184 moles of octane you will need:

0.184 moles C₈H₁₈ ₓ (25/2 moles O₂ / 1 mole C₈H₁₈) = <em>2.3 moles of oxygen</em>

As you have just 0.594 moles of oxygen, <em>Oxygen is limiting reactant.</em>

Based on chemical equation, 25/2 of O₂ produce 8 moles of CO₂, that means theoretical yield of CO₂ with 0.594 moles of O₂ is:

0.594 moles O₂ ₓ (8 moles CO₂ / 25/2 moles O₂) = 0.380 moles of CO₂

But, as yield of products is 87%, moles produced of CO₂ are:

0.380 moles of CO₂ ₓ 87% = 0.331 moles CO₂ are produced.

As molar mass of CO₂ is 44g/mol, mass of CO₂ in 0.331 moles is:

0.331 moles CO₂ ₓ (44g / mol) =

<h3>14.5g of CO₂ are produced</h3>
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3 years ago
How many moles are in 2.0 grams of Na?
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Answer:

46

Explanation:

Sodium metal has a molar mass of  

22.99

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