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Anestetic [448]
3 years ago
9

https://Suppose that the concentration of CO2 available for the Calvin cycle decreased by 50% (because the stomata closed to con

serve water). Which statement correctly describes how O2 production would be affected? (Assume that the light intensity does not change.)/105793539/ch-10-flash-cards/ . A. The rate of O2 production would remain the same because light reactions are independant of Calvin Cycle B. The rate of O2 production would remain the same because the light intensity did not change. C. The rate of O2 production would decrease because the rate of ADP
Chemistry
1 answer:
Ipatiy [6.2K]3 years ago
5 0

Answer: C. The rate of O2 production would decrease because the rate of ADP and NADP+ production by the Calvin cycle would decrease

Explanation: It is true that the Calvin Cycle is not directly dependent on light, but it is indirectly dependent on light because the energy carriers (ATP and NADPH) are produced by light-dependent reactions. Carbon dioxide and two other components (ribulose bisphosphate carboxylase and three molecules of ribulose bisphosphate) are the ones to initiate the light-independent reactions. Thus, the concentration of CO2 will determine the rate of ADP and NADP+ production, which will directly affect the rate of production of O2.

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Consider the reaction below. 2Al2O3 4Al + 3O2 What is the mole ratio of oxygen to aluminum?
DiKsa [7]
The answer is 3/4.

The coefficient next to each reactant represents the amount of moles. The compound for oxygen is O2 and the compound for aluminum is 4. We can see that the number next to O2 is 3 and the number next to aluminum is 4.
8 0
3 years ago
Read 2 more answers
Calculate the unit cell edge length for an 85 wt% fe-15 wt% v alloy. All of the vanadium is in solid solution, and, at room temp
Lady bird [3.3K]

Answer is 0.289nm.

Explanation: The wt % of Fe and wt % of V is given for a Fe-V alloy.

wt % of Fe in Fe-V alloy = 85%

wt % of V in Fe-V alloy = 15%

We need to calculate edge length of the unit cell having bcc structure.

Using density formula,

\rho_{ave}=\frac{Z\times M_{ave}}{a^3\times N_A}

For calculating edge length,

a=(\frac{Z\times M_{ave}}{\rho_{ave}\times N_A})^{1/3}

For calculating M_{ave}, we use the formula

M_{ave}= \frac{100}{\frac{(wt\%)_{Fe}}{M_{Fe}}+\frac{(wt\%)_{V}}{M_V}}

Similarly for calculating (\rho)_{ave}, we use the formula

\rho_{ave}= \frac{100}{\frac{(wt\%)_{Fe}}{\rho_{Fe}}+\frac{(wt\%)_{V}}{\rho_V}}

From the periodic table, masses of the two elements can be written

M_{Fe}= 55.85g/mol

M_{V}=50.941g/mol

Specific density of both the elements are

(\rho)_{Fe}=7.874g/cm^3\\(\rho)_{V}=6.10g/cm^3

Putting  M_{ave} and \rho_{ave} formula's in edge length formula, we get

a=\left [\frac{Z\left (\frac{100}{\frac{(wt\%)_{Fe}}{M_{Fe}}+\frac{(wt\%)_{Fe}}{M_{Fe}}}  \right )}{N_A\left (\frac{100}{\frac{(wt\%)_V}{\rho_V}+\frac{(wt\%)_V}{\rho_V}}  \right )}  \right ]^{1/3}

a=\left [\frac{2atoms/\text{unit cell}\left (\frac{100}{\frac{85\%}{55.85g/mol}+\frac{15\%}{50.941g/mol}}  \right )}{(6.023\times10^{23}atoms/mol)\left (\frac{100}{\frac{85\%}{7.874g/cm^3}+\frac{15\%}{6.10g/cm^3}}  \right )}  \right ]^{1/3}

By calculating, we get

a=2.89\times10^{-8}cm=0.289nm

7 0
2 years ago
Michela and Simone are camping in a tent during some hot weather. They
eimsori [14]

Answer:

i think that the wet cloth will keep the coolness inside the water instead of evaporating and getting warm

Explanation:

8 0
2 years ago
What is the correct name for the compound H2O
Deffense [45]

<u>Answer:</u>

The common name for the compound H2O is water.

<u>Explanation:</u>

The systemic name of H2O is Dihydrogen monoxide.

8 0
2 years ago
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Why do lithium (Li) and sodium (Na) have similar properties?
ella [17]
B, they belong to group 1

A: Li is period 2 and Na is period 3

C: Na has one more electron shell

D: Not related to how it is spelled
8 0
2 years ago
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