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Anestetic [448]
3 years ago
9

https://Suppose that the concentration of CO2 available for the Calvin cycle decreased by 50% (because the stomata closed to con

serve water). Which statement correctly describes how O2 production would be affected? (Assume that the light intensity does not change.)/105793539/ch-10-flash-cards/ . A. The rate of O2 production would remain the same because light reactions are independant of Calvin Cycle B. The rate of O2 production would remain the same because the light intensity did not change. C. The rate of O2 production would decrease because the rate of ADP
Chemistry
1 answer:
Ipatiy [6.2K]3 years ago
5 0

Answer: C. The rate of O2 production would decrease because the rate of ADP and NADP+ production by the Calvin cycle would decrease

Explanation: It is true that the Calvin Cycle is not directly dependent on light, but it is indirectly dependent on light because the energy carriers (ATP and NADPH) are produced by light-dependent reactions. Carbon dioxide and two other components (ribulose bisphosphate carboxylase and three molecules of ribulose bisphosphate) are the ones to initiate the light-independent reactions. Thus, the concentration of CO2 will determine the rate of ADP and NADP+ production, which will directly affect the rate of production of O2.

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Use the following information S(s)+O2(g)→SO2(g), ΔH∘ = -296.8kJ SO2(g)+12O2(g)→SO3(g) , ΔH∘ = -98.9kJ to calculate ΔH∘f for H2SO
Irina-Kira [14]

Answer : The enthalpy of formation of H_2SO_4 is, -812.4 kJ/mole

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The formation of H_2SO_4 will be,

S+H_2+2O_2\rightarrow H_2SO_4    \Delta H_{formation}=?

The intermediate balanced chemical reaction will be,

(1) S+O_2\rightarrow SO_2     \Delta H_1=-298.2

(2) SO_2+\frac{1}{2}O_2\rightarrow SO_3    \Delta H_2=-98.2

(3) SO_3+H_2O\rightarrow H_2SO_4    \Delta H_3=-130.2

(4) H_2+\frac{1}{2}O_2\rightarrow H_2O    \Delta H_4=-285.8

Now adding all the equations, we get the expression for enthalpy of formation of H_2SO_4 will be,

\Delta H_{formation}=\Delta H_1+\Delta H_2+\Delta H_3+\Delta H_4

\Delta H=(-298.2)+(-98.2)+(-130.2)+(-285.8)

\Delta H=-812.4kJ/mol

Therefore, the enthalpy of formation of H_2SO_4 is, -812.4 kJ/mole

3 0
3 years ago
Which particles have the same mass?
Mazyrski [523]
It would be A. proton and electron
6 0
3 years ago
Questions 18-20 refer to the reaction 2NH3 (g) ↔ N2 (g) + 3H2 (g), and ΔH = 92.2 kJ.
Fittoniya [83]
18. <span>Answer is </span>A

<span>  
<span>Since the enthalpy of reaction is positive, the forward reaction is<span> an endothermic reaction which means the energy is gained from the surrounding to happen the reaction. If the temperature decreases, according to the </span></span>Le Chatelier's principle, the system tries to become equilibrium by increasing temperature. Since forward reaction is endothermic (because of the bond breaking), the backward reaction is exothermic (because of the bond making) which releases the energy to the surroundings. This makes the increase of temperature. So if the backward reaction is promoted because of the decrease of temperature, then the concentration of H</span><span>₂ will decrease.</span>

<span>
</span>

19. Answer is A.

The reactant side has 2 moles/molecules of reactants and the product side has 4 moles/molecules of products which come from 1 N₂(g) and 3 H₂<span>(g). If the pressure is reduced in the system, according to the Le Chatelier's principle, the system tries to increase the pressure. </span><span>Hence, forward reaction is promoted because of the higher number of molecules in product side. If the forward reaction is promoted, the concentration of NH</span>₃(g) will decreased.


<span>20. </span>Answer is C.

If the concentration of reactant is increased in the system, according to the Le Chatelier's principle, the system tries to reduce the concentration of that reactant. So if NH₃(g) concentration is increased, then to be equilibrium, the forward reaction will be promoted. Then the concentration of N₂<span>(g) will increase.</span>

<span> </span>

4 0
2 years ago
10) Air masses are different in many ways. Which of these is NOT different?
grandymaker [24]

Answer:D. Ratio of oxygen/nitrogen

Explanation: the ratio will never change no matter the air pressure!

7 0
2 years ago
Place the following elements in order of increasing electronegativity.K Cs PA. K &lt; P &lt; CsB. P &lt; Cs &lt; KC. Cs &lt; K &
skad [1K]

Answer:

C. Cs < K < P

Explanation:

Electronegativity is the basically the tendency of an atom to attract electrons. The pauling scale is used to quantify electronegativity, the most electronegative element; fluorine has a value of 4.0 and francium, the least electronegative element has a value of 0.7

The electronegative values of the following elements are given as;

K = 0.82

Cs =0.79

P = 2.19

Arranging in order of increasing electronegativity, we have;

Cs < K < P. The correct option is;

C. Cs < K < P

5 0
3 years ago
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