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1 year ago

Help me due today ASAP

Mathematics

1 answer:

Allisa [31]1 year ago

4 0

Answer:

He walked for 70 minutes

Step-by-step explanation:

Find the unit rate by dividing 20/4 to get 5. Then you multiply 14x5 and get 70.

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In 1911, the temperature in Rapid City,

Sliva [168]

The 3.1 °F/min rate of change of the temperature and 15 minutes change duration gives the change in temperature as 46.5 °F

<h3>How can the change in temperature be found from the rate of change?</h3>

The rate at which the temperature changed = 3.1 °F/min

The duration of the change in temperature = 15 minutes

The relationship between the change in temperature, the rate of change in temperature and the time can be presented as follows;

$3.1 ^{\circ} F/min = \frac{ \delta T }{\delta t} = \frac{ \Delta T }{ \Delta t}$

Where;

∆T = The required change in temperature

∆t = The duration of the change = 15 minutes

Which gives;

∆T = 3.1°F/min × 15 minutes = 46.5 °F

The change in temperature, ∆T = 46.5 °F

Learn more about the rate of change of a variable here:

brainly.com/question/10208814

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8 0

11 months ago

The cost of going to the big playland park for a family is given by C=15x + 50, where C represents the cost and x represents the

IgorC [24]

Set the equation to 125.

15x+50= 125

Subtract 50.

15x= 75

Divide by 15 into both sides.

x= 5

5 family members went.

I hope this helps!
~cupcake

3 0

2 years ago

Divide 5/9 and round to the nearest tenth

n200080 [17]

5/9 equals 0.5555555556
The rounded answer would be 0.6
c:

5 0

2 years ago

Read 2 more answers

Solve:<br><br> r<br> 5<br> - 6 = -1

Leona [35]

That's right, 5- 6= -1

3 0

2 years ago

Read 2 more answers

Compute x/y if

Marysya12 [62]

Let first consider the equations one by one and will be solving one by one ;

${:\implies \quad \sf x+\dfrac{1}{y}=4}$

Multiplying both sides by y will lead ;

${:\implies \quad \sf xy+1=4y}$

${:\implies \quad \boxed{\sf xy=4y-1\quad \cdots \cdots(i)}}$

Now, consider the second equation which is ;

${:\implies \quad \sf y+\dfrac{1}{x}=\dfrac14}$

Multiplying both sides by x will yield

${:\implies \quad \sf xy+1=\dfrac{x}{4}}$

${:\implies \quad \sf xy=\dfrac{x}{4}-1}$

${:\implies \quad \boxed{\sf xy=\dfrac{x-4}{4}\quad \cdots \cdots(ii)}}$

As LHS of both equations (i) and (ii) are same, so equating both will yield;

${:\implies \quad \sf 4y-1=\dfrac{x-4}{4}}$

Multiplying both sides by 4 will yield

${:\implies \quad \sf 16y-4=x-4}$

${:\implies \quad \sf 16y=x}$

Dividing both sides by y will yield :

${:\implies \quad \boxed{\bf{\dfrac{x}{y}=16}}}$

<em>Hence, the required answer is 16</em>

5 0

1 year ago