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2 years ago

https://lh5.googleusercontent.com/nNcMGuld4KbRoBooDf5Liva-NAJyj-IEknnSniAdiBKPNhKWtKqEw2SwN2uQUidgVX1Vh4rDHA=w739

Mathematics

2 answers:

fgiga [73]2 years ago

7 0

Answer:

The answer is F: 108

Step-by-step explanation:

144 - 108 = 36

108 ÷ 3 = 36

Marta_Voda [28]2 years ago

6 0

Answer:

giytg8h0ygrubigrfbk

Step-by-step explanation:

You might be interested in

HELP ME PLEASE............................................................

mestny [16]

Answer:

2√6

Step-by-step explanation:

find the hypotenuse of the triangle thats 3 and 7

pythagorean

3 squared + 7 squared

16 + 49 = 57

√57 is the hypotenuse

√57 is also the base of the triangle that has side thats 9

pythagorean theorem

x squared + √57 squared = 9 squared

x^2 + 57 = 81

x^2 = 81 - 57

x^2 = 24

x = √24

x = √4 * √6

x = 2√6

7 0

1 year ago

Stella buys 6 tacos and 4 enchiladas for 52 dollars. Eliana buys 7 tacos and 9 enchilladas for 78 dollars.

Firdavs [7]

Answer:

Let tacos be x and enchiladas be y

6 tacos + 4 enchiladas = 52

becomes

6x+4y=52

^^that's our first equation

Now, the second equation

7 tacos + 9 enchiladas = 78

7x+9y = 78

^^^that's our second equation

Isolate y in the first equation:

6x+4y=52

4y=52-6x

y = (52-6x)/4

^^^Let's call this equation 3

Now, sub-in equation 3 into equation 2

*replace the y*

Equation 2: 7x+9y = 78

Sub-in

7x+ <u>9 ( (52-6x)/4)</u> = 78

Do some algebra (get your x terms on one side) and you will find your x value

7x + <u>117 - 13.5x</u> = 78

(7x-13.5x) = 78-117 *get your x terms on one side

x=6

That's the cost of one taco.

Now, find y. Pick an equation (1,2 or 3). Let's pick 3 since y is already isolated.

All you do is plug in your x value.

Equation 3: y = (52-6x)/4

y= (52 -6(6))/4

...

You should be able to solve this on your own

Step-by-step explanation:

:)) You can solve for y now

5 0

1 year ago

MO is twice as long as MN. NO= 36 cm. What lengths must NM be between in order for MNO to be formed?

Nataliya [291]

Answer:

Length of NM is 36 cm

Step-by-step explanation:

Length of MN + Length of NO = Length of MNO (Or only MO)

$X + 36 = 2X$

$2X - X = 36$

$X = 36$ cm

Thus, length of MN is equal to length of NO i.e 36 cm

The line MNO has point N, that bisect it into two equal half.

Thus, the line MNO has two parts

Total length of line MNO = MN + NO = $36 + 36 = 72$ cm

4 0

2 years ago

mila has completed 4 birdhouses. thats is 40% of the bitdhouses she wants to build.how many birdhouses does she want to build

aivan3 [116]

Answer:

10 birdhouses

Step-by-step explanation:

floor gang aooh sub to pewdiepie

7 0

2 years ago

Car colors preference change over the years and according to the particular model that the customer selects. In a recent year, 1

Margarita [4]

Answer:

99.05% probabilitiy that at most six cars are black.

Step-by-step explanation:

For each luxury car, there are only two possible outcomes. Either it is black, or it is not black. The probability of a luxury car being black is independent from other luxury cars. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

$p = 0.1, n = 25$

If 25 cars of that year and type are randomly selected, find the probabilitiy that at most six cars are black.

$P(X \leq 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{25,0}.(0.1)^{0}.(0.9)^{25} = 0.0718$

$P(X = 1) = C_{25,1}.(0.1)^{1}.(0.9)^{24} = 0.1994$

$P(X = 2) = C_{25,2}.(0.1)^{2}.(0.9)^{23} = 0.2659$

$P(X = 3) = C_{25,3}.(0.1)^{3}.(0.9)^{22} = 0.2265$

$P(X = 4) = C_{25,4}.(0.1)^{4}.(0.9)^{21} = 0.1384$

$P(X = 5) = C_{25,5}.(0.1)^{5}.(0.9)^{20} = 0.0646$

$P(X = 6) = C_{25,6}.(0.1)^{6}.(0.9)^{19} = 0.0239$

$P(X \leq 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) = 0.0718 + 0.1994 + 0.2659 + 0.2265 + 0.1384 + 0.0646 + 0.0239 = 0.9905$

99.05% probabilitiy that at most six cars are black.

7 0

3 years ago