All categories

1 year ago

.

Mathematics

1 answer:

Mariana [72]1 year ago

3 0

The simple interest rate is $46,800

<h3>What is simple interest?</h3>

Simple interest serves as the interest that is based on the principal amount of a loan or in some cases the deposit in a savings account.

interest rate = 6.5%= 6.5/100= 0.065

time = 12 years

principal = $60,000

Simple interest formular =(Principal x Interest Rate x Time)/100

Simple interest = (12* 0.065* 60000)/100

=$46,800

Therefore, simple interest rate is $46,800

Learn more about simple interest at:

brainly.com/question/20690803

#SPJ1

You might be interested in

What is the approximate surface area of a cylinder that's base has a radius of 2, and it's lateral rectangle has a length of 6.2

Kisachek [45]

Answer:

Surface area of cylinder = 50.26 unit² (Approx.)

Step-by-step explanation:

Given:

Radius of base r = 2 units

Width of lateral rectangle = 4 units

Length of lateral rectangle = 6.28 units

Find:

Surface area of cylinder

Computation:

Surface area of cylinder = 2[Area of base] + Area of lateral rectangle

Surface area of cylinder = 2[πr²] + [l][b]

Surface area of cylinder = 2[(22/7)(2)²] + [6.28][4]

Surface area of cylinder = 2[(22/7)(4)] + 25.12

Surface area of cylinder = 25.14 + 25.12

Surface area of cylinder = 50.26

Surface area of cylinder = 50.26 unit² (Approx.)

7 0

3 years ago

Angle psr measures 99°. what is the measure of psq in degrees?

Snezhnost [94]

Assuming that point s is the vertex of the angle and that line sq is between angle psr. We can get the correct measurement of angle psq by subtracting 99 degrees with the measurement of the angle made by qsr. Hope this helps. Have a nice day.

6 0

3 years ago

Hi guys I need 3 minus and plus operations with answer thx!

nata0808 [166]

1999+1001=3000 1091+1009=3000 2000+1000=3000

3000-1001=1999 3000-1009=1091 3000-2000=1000

8 0

2 years ago

There are 75 milligrams of cholesterol in a 3.5 ounce serving of lobster. How much cholesterol is in 6ounces of lobster

Maru [420]

Hence, the amount of cholesterol in 6 ounces of lobster will be 128.58 milligrams

Step-by-step explanation:

Given

Cholesterol in 3.5 ounces = 75 mg

Cholesterol in 6 ounces =x= ?

This can be worked out by using proportions

It can be written as:

$\frac{75}{3.5}=\frac{x}{6}\\21.43=\frac{x}{6}\\Multiplying\ both\ sides\ by\ 6\\21.43*6=x\\x=128.58\ mg$

Hence, the amount of cholesterol in 6 ounces of lobster will be 128.58 milligrams

Keywords: Proportions, Conversion

Learn more about proportions at:

#LearnwithBrainly

8 0

3 years ago

What is Limit of StartFraction StartRoot x + 1 EndRoot minus 2 Over x minus 3 EndFraction as x approaches 3?

scoray [572]

Answer:

$\displaystyle \lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} = \boxed{ \frac{1}{4} }$

General Formulas and Concepts:

Calculus

Limits

Limit Rule [Variable Direct Substitution]:
$\displaystyle \lim_{x \to c} x = c$

Special Limit Rule [L’Hopital’s Rule]:
$\displaystyle \lim_{x \to c} \frac{f(x)}{g(x)} = \lim_{x \to c} \frac{f'(x)}{g'(x)}$

Differentiation

Derivatives
Derivative Notation

Derivative Property [Addition/Subtraction]:
$\displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)]$
Derivative Rule [Basic Power Rule]:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]:
$\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Step-by-step explanation:

Step 1: Define

Identify given limit.

$\displaystyle \lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3}$

Step 2: Find Limit

Let's start out by directly evaluating the limit:

[Limit] Apply Limit Rule [Variable Direct Substitution]:
$\displaystyle \lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} = \frac{\sqrt{3 + 1} - 2}{3 - 3}$
Evaluate:
$\displaystyle \begin{aligned}\lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} & = \frac{\sqrt{3 + 1} - 2}{3 - 3} \\& = \frac{0}{0} \leftarrow \\\end{aligned}$

When we do evaluate the limit directly, we end up with an indeterminant form. We can now use L' Hopital's Rule to simply the limit:

[Limit] Apply Limit Rule [L' Hopital's Rule]:
$\displaystyle \begin{aligned}\lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} & = \lim_{x \to 3} \frac{(\sqrt{x + 1} - 2)'}{(x - 3)'} \\\end{aligned}$
[Limit] Differentiate [Derivative Rules and Properties]:
$\displaystyle \begin{aligned}\lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} & = \lim_{x \to 3} \frac{(\sqrt{x + 1} - 2)'}{(x - 3)'} \\& = \lim_{x \to 3} \frac{1}{2\sqrt{x + 1}} \leftarrow \\\end{aligned}$
[Limit] Apply Limit Rule [Variable Direct Substitution]:
$\displaystyle \begin{aligned}\lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} & = \lim_{x \to 3} \frac{(\sqrt{x + 1} - 2)'}{(x - 3)'} \\& = \lim_{x \to 3} \frac{1}{2\sqrt{x + 1}} \\& = \frac{1}{2\sqrt{3 + 1}} \leftarrow \\\end{aligned}$
Evaluate:
$\displaystyle \begin{aligned}\lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} & = \lim_{x \to 3} \frac{(\sqrt{x + 1} - 2)'}{(x - 3)'} \\& = \lim_{x \to 3} \frac{1}{2\sqrt{x + 1}} \\& = \frac{1}{2\sqrt{3 + 1}} \\& = \boxed{ \frac{1}{4} } \\\end{aligned}$

∴ we have evaluated the given limit.

___

Learn more about limits: brainly.com/question/27807253

Learn more about Calculus: brainly.com/question/27805589

___

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Limits

3 0

1 year ago