There are no solutions. These two equations never intersect
Answer: point C = (3.75, 1.5)
Step-by-step explanation:
As the direction of the distance is from A to B, we need to down the y-axis and along (to the right) the x-axis.
Find the distance between the x-coordinates of both points by subtracting the x-coordinate of A from the x-coordinate of B:
5 - 0 = 5
3/4 of the length of this distance = 0.75 x 5 = 3.75
So the x-coordinate of C will be the sum of the distance (3.75) and the x-coordinate of A (as we are "travelling" from A to B):
3.75 + 0 = 3.75
Find the distance between the y-coordinates of both points by subtracting the y-coordinate of B from the y-coordinate of A:
3 - 1 = 2
3/4 of the length of this distance = 0.75 x 2 = 1.5
So the y-coordinate of C will be the y-coordinate of A minus the distance (1.5):
3 - 1.5 = 1.5
Therefore, point C = (3.75, 1.5)
Hope that helps - i dont know what u meant by option 1,2,3 so if u have an questions or i did it wrong i will fix it <3
Answer:
3) (2,-9)
4) (0,-5)
5) (1,-8)
Step-by-step explanation:
3)
The vertex will occur between you x-intercepts.
You already found that happens at x=2.
To find the corresponding y-coordinate, replace x in
f(x)=(x+1)(x-5) with 2:
f(2)=(2+1)(2-5)
f(2)=(3)(-3)
f(2)=-9
So the vertex is (2,-9).
4)
The y-intercept is when x=0.
So in f(x)=(x+1)(x-5) replace x with 0:
f(0)=(0+1)(0-5)
f(0)=(1)(-5)
f(0)=-5
So the y-intercept is (0,-5).
5)
To find another point just plug in anything besides any x already used.
We preferably want to use a value of x that will keep us on their grid however far up,down,left, or right their grid goes out. So I'm going to choose something close to the vertex which is at x=2. Let's go with x=1.
So replace x in f(x)=(x+1)(x-5) with x=1:
f(1)=(1+1)(1-5)
f(1)=(2)(-4)
f(1)=-8
So another point to graph is (1,-8).
