Round 654 to the nearest hundred

Based on the diagram above, which of the following does not make q and parallel

iragen [17]

C. Because it only gives the measure of angles on line p and not line q

3 0

2 years ago

WILL GIVE BRAINLIEST

Alja [10]

A. The pair of linear equations are: x + y = 55 and y = x + 25

B. Number of time she spend running everyday is: 15 minutes.

C. It is not possible.

<h3>How to Write a System of Linear Equations?</h3>

A system of equations consist of linear equations that have unknown variables whose values make the linear equations in the system true.

Part A: To write a pair of linear equations, do the following,

Let x represent the time Jackie runs

Let y represent the time Jackie dances

We are given that, Jackie runs and dances for a total of 55 minutes every day, therefore, the first linear equation would be:

x + y = 55 --> equation 1

We are also given that Jackie dances for 25 minutes longer than she runs, therefore, the second linear equation would be:

y = x + 25 --> equation 2

Therefore, the two pair of linear equations that shows the relationship between the number of minutes Jackie runs and dances everyday are:

x + y = 55

y = x + 25

Part B: Substitute y = (x + 25) into equation 1

x + y = 55 --> equation 1

x + x + 25 = 55

2x + 25 = 55

2x = 55 - 25

2x = 30

x = 15

Therefore, the number of time she spend running everyday is: 15 minutes.

Part C:

If she spent 45 minutes dancing (y = 45), and x = 15, substitute the values into x + y = 55 to find out if it is possible.

15 + 45 = 55

60 = 55 (not true)

Therefore, it is not possible.

Learn more about the system of equations on:

brainly.com/question/13729904

#SPJ1

8 0

2 years ago

find the permimter of the quadrilateral if x=2 the perimiter is in inches the perimiters are (4x2+8x) (31 ) (7x+30) (3x2-5x+20)

d1i1m1o1n [39]

Answer:

115

Step-by-step explanation:

4*2+8(2) = 24

31

7(2)+30 = 44

3*2-5(2)+20 = 6-10+20 = -4+20 = 16

24+31+44+16

115

8 0

3 years ago

Read 2 more answers

Suppose that five ones and four zeros are arranged around a circle. Between any two equal bits you insert a 0 and between any tw

PolarNik [594]

Answer:

Using backward reasoning we want to show that "We can never get nine 0's".

Step-by-step explanation:

Basically in order to create nine 0's, the previous step had to have all 0's or all 1's. There is no other way possible, because between any two equal bits you insert a 0.

If we consider two cases for the second-to-last step:

There were 9 0's:

We obtain nine 0's if all bits in the previous step were the same, thus all bit were 0's or all bits were 1's. If the previous step contained all 0's, then we have the same case as the current iteration step. Since initially the circle did not contain only 0's, the circle had to contain something else than only 0's at some point and thus there exists a point where the circle contained only 1's.

There were 9 1's:

A circle contains only 1's, if every pair of the consecutive nine digits is different. However this is impossible, because there are five 1's and four 0's (we have an odd number of bits!), thus if the 1's and 0's alternate, then we obtain that 1's that will be next to each other (which would result in a 1 in the next step). Thus, we obtained a contradiction and thus assumption that the circle contains nine 0's after iteratins the procedure is false. This then means that you can never get nine 0's.

To summarize, in order to create nine 0's, the previous step had to have all 0's or al 1's. As we didn't start the arrange with all 0's, the only way is having all 1's, but having all 1's will not be possible in our case since we have an odd number of bits.

5 0

3 years ago

Solve the inequality for t. 11 ≤ t + 4 Simplify your answer as much as possible.

Softa [21]

Answer:

t≥7

Step-by-step explanation:

11≤t+4

4 moves to the other side hence its sign changes

11-4≤t

7≤t

they change sides

t≥7

the sign was facing t so this does not change

8 0

3 years ago

Read 2 more answers