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Montano1993 [528]
3 years ago
9

What two facts you double to find 8x4? explain

Mathematics
2 answers:
svlad2 [7]3 years ago
4 0
You would double 16 because 16+16=32
horsena [70]3 years ago
3 0
You can also do 4 times 8
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(2x^3+4x^2-3)+(6x^3+4x-4)<br>​
sukhopar [10]

Answer:

8x^3 + 4x^2 + 4x -7

Step-by-step explanation:

Add like terms.

8 0
3 years ago
Read 2 more answers
Use for Questions 11-15
Juli2301 [7.4K]

Step-by-step explanation:

12. 136/300

=52%

13.45/300

=15%

6 0
2 years ago
I'd really appreciate it if you'd show your work for the question, it'd be lots of help! I'll give Brainliest! :)
Sonbull [250]

Let the number of ride tickets = x tickets.

And the total cost is given by y.

Fair charges $1.25 per ticket for the rides.

Johnny bought = 25 tickets.

Therefore, cost of 25 tickets @ $1.25 per ticket = 25 × 1.25 = $31.25

Total amount spent at the fair = $43.75.

Fair admission charge = Total amount spent - Cost of 25 tickets = 43.75 - 31.25 =$12.50.

Therefore, total cost of the fair = Fix fair admission charge + total cost of x number of tickets @1.25 each.

y = 12.50 + 1.25x.

Therefore, y = 12.50 + 1.25x is the linear equation that can be used to determine the cost for anyone who only pays for x ride tickets and $ 12.50 fair admission.

8 0
3 years ago
What percentage is the shaded area
Sati [7]
90%, as each section is 10 percent!
7 0
3 years ago
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A wind turbine is located at the top of a hill where the wind blows steadily at 12 m/s, and stands 37 m tall. The air then exits
marta [7]

Answer:

Power generated = 4.315 kW

Step-by-step explanation:

Given,

  • speed of wind when enters into the turbine, V = 12 m/s
  • speed of wind when exits from the turbine, U = 9 m/s
  • mass flow rate of the wind, m = 137 kg/s

According to the law of conservation of energy

Energy generated = change in kinetic energy

Since, the air is exiting at same elevation. So, we will consider only kinetic energy.

Energy generated in one second will be given by,

E\ =\ \dfrac{1}{2}.mV^2-\dfrac{1}{2}.m.U^2

   =\ \dfrac{1}{2}\times 137\times (12)^2-\dfrac{1}{2}\times 137\times (9)^2

   =4315.5 J

   = 4.315 kJ

So, energy is generated in one second = 4.315 kJ

Power generated can be given by,

P\ =\ \dfrac{\textrm{energy generated}}{time}

And the energy is generated is already in per second so power generated will be 4.315 kW.

   

   

   

   

   

8 0
3 years ago
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