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DIA [1.3K]
1 year ago
13

The average weight of newborn child 7.5 pounds with a tolerance of pounds Write an absolute value inequality describing the weig

ht of a child
Mathematics
1 answer:
Shkiper50 [21]1 year ago
8 0

The average weight of a child  is

2 Years 26.5 lb (12.02 kg)

3 Years 31.5 lb (14.29 kg)

4 Years 34.0 lb (15.42 kg)

5 Years 39.5 lb (17.92 kg)

6 Years 44.0 lb (19.96 kg)

7 Years 49.5 lb (22.45 kg)

8 Years 57.0 lb (25.85 kg)

9 Years 62.0 lb (28.12 kg)

10 Years 70.5 lb (31.98 kg)

11 Years 81.5 lb (36.97 kg)

12 Years 91.5 lb (41.5 kg)

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Why is Li incorrect in saying that the graph shows a direct variation
qwelly [4]

Answer:

The answer B

Step-by-step explanation:

7 0
3 years ago
If x varies inversely as y, and x=6 when y=72, find x when y=36
Hoochie [10]

Answer:

12

Step-by-step explanation:

x = k/y           Multiply each side by y

k = xy            Insert values

  = 6 × 72

  = 432

x = 432/y     Let y = 36

  = 432/36

x = 12

7 0
4 years ago
The hypotenuse of an isosceles right triangle is 16 centimeters. Find the length of the 2 other sides of the triangle to the nea
scZoUnD [109]
Right triangle means we can use a^2+b^2=c^2
isosceles means 2 sides are equal legnths

the hypotenuse is normally the longest side so the equal sides are the other sides so therefore
a=b
therefor
(a^2)+(a^2)=c^2
2(a^2)=16^2
2(a^2)=256
divde both sides by 2
a^2=8
the side legnth of the other 2 sides is the square root of 8 which is aprox 2.8284271247452
but we only want the tenth so we look at the hundreths as well
2.82
round to the nearest tenth
2.8 cm is the answer of the legnths
4 0
3 years ago
Define an exponential function, h(x), which passes through the points (1,16) and(5, 1296). Enter your answer in the form axb^xh(
Lerok [7]

Define an exponential function, h(x), which passes through the points (1,16) and

(5, 1296). Enter your answer in the form axb^x

the equation is of the form

y=a(b)^x

we have

point (1,16)

so

For x=1, y=16

substitute

\begin{gathered} 16=a(b)^1 \\ 16=a\cdot b \end{gathered}

isolate the variable a

a=\frac{16}{b}

Point (5,1296)

For x=5, y=1,296

substitute

1,296=a(b)^5

substitute equation 1 in equation 2

1,296=(\frac{16}{b})\cdot b^5

solve for b

\begin{gathered} \frac{1296}{16}=b^4 \\ b^4=81 \\ b=3 \end{gathered}

Find the value of a

a=16/3

therefore

the equation is

y=\frac{16}{3}\cdot(3)^x

see the attached figure to better understand the problem

6 0
1 year ago
Need help geometry question central angles and arcs?
Maksim231197 [3]

Answer:

135

Step-by-step explanation:

360-90=270

270/2=135

7 0
3 years ago
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