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myrzilka [38]
1 year ago
7

Define an exponential function, h(x), which passes through the points (1,16) and(5, 1296). Enter your answer in the form axb^xh(

x) =
Mathematics
1 answer:
Lerok [7]1 year ago
6 0

Define an exponential function, h(x), which passes through the points (1,16) and

(5, 1296). Enter your answer in the form axb^x

the equation is of the form

y=a(b)^x

we have

point (1,16)

so

For x=1, y=16

substitute

\begin{gathered} 16=a(b)^1 \\ 16=a\cdot b \end{gathered}

isolate the variable a

a=\frac{16}{b}

Point (5,1296)

For x=5, y=1,296

substitute

1,296=a(b)^5

substitute equation 1 in equation 2

1,296=(\frac{16}{b})\cdot b^5

solve for b

\begin{gathered} \frac{1296}{16}=b^4 \\ b^4=81 \\ b=3 \end{gathered}

Find the value of a

a=16/3

therefore

the equation is

y=\frac{16}{3}\cdot(3)^x

see the attached figure to better understand the problem

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What is the image of point (-7, 7) for mapping (x, y), (x- 1, x+ 6)
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A class is selling magazines as a fund raiser. Of the 500 magazines sold, Allie sold 1/7of them. Gary sold 0.085 of the magazine
jarptica [38.1K]
Allie sold about 71 magazines.
Gary sold about 43.
Rob sold about 45.
Felisha sold about 93.
Felisha sold the most magazines.

Elaboration:
Since Allie sold 1/7 of the 500 magazines, you must find 1/7 of 500. To do this, multiply 500 by the numerator, which is 1. Now you have \frac{500}{7}, which is the same thing as dividing 500 by 7, which is around 71.

Since Gary sold 0.085 of the magazines, you multiply this decimal by that same 500, getting about 43.

Since Rob sold 9/100 of the magazines, you once again multiply 500 by the numerator, coming out with 4,500. Then you replace the 9 with that number, so you have \frac{4,500}{100}, which is also the same thing as Allie's in the fact that you're dividing 4,500 by 100, which is 45. Therefore, Rob sold 43 magazines.

Since Felisha sold 0.185 of the magazines, you follow the same procedure as with Gary - multiply the decimal by 500, getting 93.

Hope this helps! Live long and prosper, my friend. :)
4 0
3 years ago
A cell phone costs $750 and loses 28% of its value each year. What is the value of the phone after 2 years?
Kamila [148]

Answer:

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750*exp(-.3285*n) as the value after n years.

6 0
3 years ago
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