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Mrrafil [7]
2 years ago
14

The perimeter of a rectangular swimming pool is 414 meters. The length of the pool is 7 meters more than four times the width. F

ind the length and the width
Mathematics
1 answer:
kobusy [5.1K]2 years ago
4 0

Answer:

l = \boxed{167.}\\w=\boxed{40.}

Step-by-step explanation:

Since the perimeter is 414 meters, half of the perimeter is 207 meters. We can write the following equation and solve for h.

w + l = 207\\w + (4w + 7) = 207\\5w +7 = 207\\5w = 200\\w = \boxed{40.}

Here, we substituted 4w + 7 in place of l as the problem tells us that the length of the pool is 7 meters more than 4 times the width. Solving for the width gave us 40 meters.

Using this information, we can determine that the length of the swimming pool is:

4(40) + 7 = 160 + 7 = 167.

To double-check that this is correct, we can add twice the length and twice the width to see if it equals the given perimeter:

167 + 167 + 40 + 40 =  414.

Therefore, your length and width of this swimming pool are:

l = \boxed{167.}\\w=\boxed{40.}

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Answer:

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Step-by-step explanation:

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cos theta = 36/113.84

cos theta = 0.3162

theta = arccos (0.3162)

<em>theta = 71.6 degrees </em>

<em>Hence the angle between the given vectors is 71.6 degrees </em>

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