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Kaylis [27]
3 years ago
13

Multiply and simplify

%7D%20" id="TexFormula1" title=" \frac{1}{?8} \times \frac{2}{?5} " alt=" \frac{1}{?8} \times \frac{2}{?5} " align="absmiddle" class="latex-formula">
Mathematics
1 answer:
denis-greek [22]3 years ago
8 0
\frac{1}{8} \times \frac{2}{5} = \frac{1 \times 2}{8 \times 5} = \frac{2}{40} = \frac{2 \div 2}{40 \div 2} = \frac{1}{20}
The answer is
\frac{1}{20}
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what is a decimal that is equivalent to the expression (3 x 100) + (7 x 10) + (4x1) + (6 x 0.01) + (2 x 0.001)?
-BARSIC- [3]

Answer:

374.062

Step-by-step explanation:

multiply all those and put them in the correct place.

do it just as i did my answer

3 goes first 7 goes next to 3 4 goes next to 7 add the decimal point then

put 0 since there are no tenths then put 6 then next to 6 put 2

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Workout the value of 5(x-y)
ANTONII [103]

Answer:

5x-5y

Step-by-step explanation:

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Please help me on this will give you brainliest
elena-14-01-66 [18.8K]
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3 years ago
What is the quadratic portion in this quadratic equation 7x2-12x+16=0
alexdok [17]

Answer:

x = 6/7 + (2 i sqrt(19))/7 or x = 6/7 - (2 i sqrt(19))/7

Step-by-step explanation:

Solve for x:

7 x^2 - 12 x + 16 = 0

Hint: | Write the quadratic equation in standard form.

Divide both sides by 7:

x^2 - (12 x)/7 + 16/7 = 0

Hint: | Solve the quadratic equation by completing the square.

Subtract 16/7 from both sides:

x^2 - (12 x)/7 = -16/7

Hint: | Take one half of the coefficient of x and square it, then add it to both sides.

Add 36/49 to both sides:

x^2 - (12 x)/7 + 36/49 = -76/49

Hint: | Factor the left hand side.

Write the left hand side as a square:

(x - 6/7)^2 = -76/49

Hint: | Eliminate the exponent on the left hand side.

Take the square root of both sides:

x - 6/7 = (2 i sqrt(19))/7 or x - 6/7 = -(2 i sqrt(19))/7

Hint: | Look at the first equation: Solve for x.

Add 6/7 to both sides:

x = 6/7 + (2 i sqrt(19))/7 or x - 6/7 = -(2 i sqrt(19))/7

Hint: | Look at the second equation: Solve for x.

Add 6/7 to both sides:

Answer:  x = 6/7 + (2 i sqrt(19))/7 or x = 6/7 - (2 i sqrt(19))/7

6 0
3 years ago
A first order decomposition reaction has a half-life of 64yr. What percentage of the original amount is left after 135years. (gi
vlabodo [156]

Answer:

23.2%

Step-by-step explanation:

First we need to find how many half lives 135 years is:

135 ÷ 64 = 2.109375

Now we divide 100% by 2 to the power of the number of half lives. This is how you calculate the percentage of the original amount left. If you have the original mass, you can substitute that in instead of 100%:

100 ÷ 2^{2.109375} = 23.1747390635

To 1 decimal place it is 23.2%

4 0
3 years ago
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