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dolphi86 [110]
3 years ago
15

Which is the initial value that shrinks an exponential growth function by 50%?

Mathematics
2 answers:
ValentinkaMS [17]3 years ago
7 0
Suppose that the exponential growth function is  y = 4^x.

If x = 1, then y = 4^1 = 4.
If x = 3, then y = 4^3 = 64.

Let the initial value be 1/2.

The growth function is now y = 1/2 * 4^x.

If x =1, then y = 2 which is half of the y value before adding the 1/2.

If x = 3, then y = 1/2 * 64 = 32.

Answer: 1/2
scoundrel [369]3 years ago
3 0

Answer: 1/2 D :) on Edge

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Substitute in variables [Cosine]:                                                                    \displaystyle cosx^\circ = \frac{5.8}{7.3}
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<u></u>

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<u />

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<u />

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<u />

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<u />

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