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a_sh-v [17]
2 years ago
11

Line g is shown on the graph.

Mathematics
1 answer:
bogdanovich [222]2 years ago
5 0

The equation of the line g that passes through points (-3, 2) and (0, 5), in slope-intercept form, is: y = x + 5.

<h3>How to Write the Equation of a Line in Slope-intercept Form?</h3>

Given the coordinates of two points that lie on a straight line on a graph, the equation that represents the line in slope-intercept form can be expressed as, y = mx + b, where:

Slope = m = change in y / change in x

y-intercept = b (the value of y when x = 0).

The coordinates of the two points on line g is given as:

(-3, 2) = (x1, y1)

(0, 5) = (x2, y2).

Find the slope (m) of the line:

Slope (m) = (5 - 2)/(0 - (-3))

Slope (m) = 3/3

Slope (m) = 1.

Y-intercept (b) = 5

Substitute m = 1 and = 5 into y = mx + b:

y = x + 5

The equation of the line in slope-intercept form is: y = x + 5.

Learn more about the slope-intercept equation on:

brainly.com/question/1884491

#SPJ1

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Use vieta's theorem to solve the problems.
Mnenie [13.5K]

Using Vieta's Theorem, it is found that c = 72.

<h3>What is the Vieta Theorem?</h3>
  • Suppose we have a quadratic equation, in the following format:

y = ax^2 + bx + c

  • The roots are p and q.

The Theorem states that:

p + q = -\frac{b}{a}

pq = \frac{c}{a}

In this problem, the polynomial is:

x^2 - 17x + c

Hence the coefficients are a = 1, b = -17.

Since the difference of the solutions is 1, we have that:

p - q = 1

p = 1 + q

Then, from the first equation of the Theorem:

p + q = -\frac{b}{a}

1 + q + q = 17

2q = 16

q = 8

p = 1 + q = 9

Now, from the second equation:

pq = \frac{c}{a}

72 = c

c = 72

To learn more about Vieta's Theorem, you can take a look at brainly.com/question/23509978

6 0
2 years ago
A parabola can be drawn given a focus of (5, -3) and a directrix of y=1. Write the equation of the parabola in any form.
Anna71 [15]

Answer:

(x²-10x+33)/(-8) = y

Step-by-step explanation:

The distance between any point on a parabola from both its focus and directrix are the same.

Let's say we have a point (x,y) on the parabola. We can then say that using the distance formula,

\sqrt{(x-5)^2+(y-(-3))^2}is the distance between (x,y) and the focus. Similarly, the distance between (x,y) and the directrix is |y-1| (I use absolute value here because distance is always positive). We can find this equation by taking the shortest distance from the point to the line. Because the closest point to the line will be the same x value as the point itself, the distance is simply the distance between the y value of the point and the y value of the directrix.

Equating the two equations given, we have

\sqrt{(x-5)^2+(y-(-3))^2} = |y-1|

square both sides to get

(x-5)²+(y+3)²=(y-1)²

expand the y components

(x-5)² + y²+6y+9 = y²-2y+1

subtract y²+6y+9 from both sides

(x-5)² = -8y - 8

expand the x components

x²-10x+25 = -8y - 8

add 8 to both sides to isolate the -8y

x²-10x+33 = -8y

divide both sides by -8 to isolate y

(x²-10x+33)/(-8) = y

6 0
3 years ago
I’ll give points + brainalist
notka56 [123]

Answer:

C

Step-by-step explanation:

The number of points either side of the line of best fit are equal (3 points either side) and the line is the line of best fit.

5 0
2 years ago
1. A square ABCD has the vertices A(n, n), B(n, -n), C(-n, -n), and D(-n, n). Which vertex is in Quadrant III?
andrew-mc [135]

The four quadrants and the sign of coordinates is given as follows:

Quadrant I : (n, n ) both x and y positive.

Quadrant II : ( -n,n) = x negative and y positive.

Quadrant III : ( -n,-n) = both x and y negative.

Quadrant IV: (n, -n) = x positive and y negative.

So Based on the above concept , we can say that vertex C (-n,-n) has both x and y negative and so it lies in quadrant III.

Answer is Vertex C (-n,-n)

5 0
4 years ago
Read 2 more answers
Help me please *an image is attached*
Mashutka [201]

Answer:

its C

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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