Let's start by writing an equation for this. So in overall, there will be 3 tests. Therefore, If the first two average to 92, then the third plus those two individual scores divided by 3 will need to equal 94. Lets call the new score x.
(92 x 2 + x) / 3 = 94
184 + x = 282
x = 98
Johnny will need to get a 98 on the 3rd test to raise his average to exactly 94.
I hope this helps :-)
Answer:
JL ⊥ KM
Step-by-step explanation:
JL ⊥ KM would make the quad a rhombus because JKLM is a parallelogram since opposite sides are congruent. If the diagonals of a parallelogram are perpendicular, then the quad must be a rhombus.
20% of 59.99 is 11.998 so 11.99. 59.99 - 11.99 = 48. 48x4 is 192
192$
I suppose the answer would be 3n-2N can be no greater than 4
If I’m wrong feel free to correct me