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2 years ago

The diagram shows a right-angled triangle.

Mathematics

1 answer:

amm18122 years ago

4 0

The length of the hypotenuse and the opposite side to angle x of the right triangle are 8 cm and 3 cm respectively, which gives angle x as approximately 22.0°

<h3>Which of the trigonometric ratios can be used to find x°?</h3>

A description of the parts of the triangle are;

Length of the hypotenuse side = 8 cm

Length of the opposite side to x° = 3 cm

The trigonometric ratio of the sine of x° is presented as follows;

$sin(x) = \frac{Opposite}{Hypotenuse}$

Therefore;

$sin(x) = \frac{3}{8}$

Which gives;

${x}^{ \circ} = arcsine \left( \frac{3}{8} \right) \approx {22.0}^{ \circ}$

Angle x ≈ 22.0°

Learn more about trigonometric ratios of the cosine, sines, and tangent of angles here:

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Please if anyone can answer?

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Answer:Oof your stuff looks hard!

Step-by-step explanation:

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. Hernandez bought 18 pens for her class. Highlighters cost $3 each, and gel pens cost $2.50 each. She spent a total of $50. Use

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Answer:

There are 9 highlighters and 8 gel pens

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3 years ago

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Solve eqaution 4t+9=-8t-13

LiRa [457]

Simple.....

you have:

4t+9=-8t-13

isolate the variable...

4t+9=-8t-13
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12t+9=-13

12t+9=-13
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12t=-22

t= $- \frac{11}{6}$

Thus, your answer.

3 0

3 years ago

Noise levels at 5 airports were measured in decibels yielding the following data: 152,154,139,124,120 Construct the 80% confiden

Yuri [45]

Answer:

$137.8-1.533\frac{15.595}{\sqrt{5}}=127.108$

$137.8+1.533\frac{15.595}{\sqrt{5}}=148.492$

So on this case the 80% confidence interval would be given by (127.108;148.492)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the mean and the sample deviation we can use the following formulas:

$\bar X= \sum_{i=1}^n \frac{x_i}{n}$ (2)

$s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}}$ (3)

The mean calculated for this case is $\bar X=137.8$

The sample deviation calculated $s=15.595$

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=5-1=4$

Since the Confidence is 0.80 or 80%, the value of $\alpha=0.2$ and $\alpha/2 =0.1$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.1,4)".And we see that $t_{\alpha/2}=1.533$

Now we have everything in order to replace into formula (1):

$137.8-1.533\frac{15.595}{\sqrt{5}}=127.108$

$137.8+1.533\frac{15.595}{\sqrt{5}}=148.492$

So on this case the 80% confidence interval would be given by (127.108;148.492)

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4 years ago

What is the value of −2{42 + (12)2}

Harman [31]

First we do 12*2=24
-2[42+24]=-2(66)=-132

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3 years ago