All categories

1 year ago

The diagram shows a right-angled triangle.

Mathematics

1 answer:

amm18121 year ago

4 0

The length of the hypotenuse and the opposite side to angle x of the right triangle are 8 cm and 3 cm respectively, which gives angle x as approximately 22.0°

<h3>Which of the trigonometric ratios can be used to find x°?</h3>

A description of the parts of the triangle are;

Length of the hypotenuse side = 8 cm

Length of the opposite side to x° = 3 cm

The trigonometric ratio of the sine of x° is presented as follows;

$sin(x) = \frac{Opposite}{Hypotenuse}$

Therefore;

$sin(x) = \frac{3}{8}$

Which gives;

${x}^{ \circ} = arcsine \left( \frac{3}{8} \right) \approx {22.0}^{ \circ}$

Angle x ≈ 22.0°

Learn more about trigonometric ratios of the cosine, sines, and tangent of angles here:

brainly.com/question/12172664

#SPJ1

You might be interested in

Leah deposited $50,000 in the bank. Three years later, she borrowed $40,000 for a new truck. From this description, which is the

NISA [10]

Answer: B. (Leah did not have to provide collateral.)

6 0

3 years ago

A stationary store has decided to accept a large shipment of ball-point pens if an inspection of 17 randomly selected pens yield

Leno4ka [110]

Answer:

0.762 = 76.2% probability that this shipment is accepted

Step-by-step explanation:

For each pen, there are only two possible outcomes. Either it is defective, or it is not. The probability of a pen being defective is independent from other pens. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

17 randomly selected pens

This means that $n = 17$

(a) Find the probability that this shipment is accepted if 10% of the total shipment is defective. (Use 3 decimal places.)

This is $P(X \leq 2)$ when $p = 0.1$ . So

$P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{17,0}.(0.1)^{0}.(0.9)^{17} = 0.167$

$P(X = 1) = C_{17,1}.(0.1)^{1}.(0.9)^{16} = 0.315$

$P(X = 2) = C_{17,2}.(0.1)^{2}.(0.9)^{15} = 0.280$

$P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.167 + 0.315 + 0.280 = 0.762$

0.762 = 76.2% probability that this shipment is accepted

8 0

3 years ago

Please help me out!!!!

Kobotan [32]

Answer:

All real numbers

Step-by-step explanation:

4(x+1) = 4x+4

Distribute

4x+4 = 4x+4

Subtract 4x from each side

4x+4-4x = 4x+4-4x

4=4

This is always true so there are infinite solutions

3 0

2 years ago

Read 2 more answers

BRAINLISTS!! 35 (69) points !!

musickatia [10]

Answer:

(A) and c

(B) and a

(D) and b

Step-by-step explanation:

these are from the calculations i got, what you do is minus the two answers you have to find n

5 0

3 years ago

Read 2 more answers

HELP ASAP STEP BY STEP FIRST TO ANSWER IS BRAINLEIST!

irina [24]

卂几丂山乇尺

_____________________

7) 8hours

8) 10 pizzas

9) 13 packets

_______________________

EXPLANATION .:

_____(7)______________

Stacy's earning per hour babysitting

= 12$

Thus on Friday to earn 36$,

she would have worked 36/12 = 3 hours

On Saturday she earned 60$,

thus the time she worked = 60/12 = 5 hours

So the total time Stacy babysited on both days = 3+5 = 8hours

_______(8)__________________

Total ounces with Marco = 147

Ounces required for 1 pizza = 13

Ounced required for 1 breadstick = 2

Now when he has already made 3 breadsticks thus he would have used 3×2 = 6 ounces

So the remaining ounces = 147-6 = 141

Hence he can make 141/13 = 10.8 or 10 pizzas.

___________(10)_____________

Mr.Dundford gives 6 pencils to each student => for 30 students the pencils required would be 30×6 = 180

Now when he had already 24 pencils Thus the remaining = 180-24 = 156

Also there are 12 pencils in a packet

=> packets required = 156/12 = 13

___________________________

___________________

____________

_______

___

8 0

3 years ago

Read 2 more answers