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Semmy [17]
2 years ago
11

The diagram shows a right-angled triangle.

Mathematics
1 answer:
amm18122 years ago
4 0

The length of the hypotenuse and the opposite side to angle<em> </em><em>x</em> of the right triangle are 8 cm and 3 cm respectively, which gives angle <em>x </em>as approximately 22.0°

<h3>Which of the trigonometric ratios can be used to find x°?</h3>

A description of the parts of the triangle are;

Length of the hypotenuse side = 8 cm

Length of the opposite side to <em>x°</em><em> </em>= 3 cm

The trigonometric ratio of the sine of x° is presented as follows;

sin(x) =  \frac{Opposite}{Hypotenuse}

Therefore;

sin(x) =  \frac{3}{8}

Which gives;

{x}^{ \circ}  = arcsine \left( \frac{3}{8}  \right)  \approx  {22.0}^{ \circ}

  • Angle<em> </em><em>x </em>≈ 22.0°

Learn more about trigonometric ratios of the cosine, sines, and tangent of angles here:

brainly.com/question/12172664

#SPJ1

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Step-by-step explanation:

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cos2A=1−2sin²A

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As required,  set A = \frac{a}{2}   &   cos a=  \frac{12}{13}    ,thus we get

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∴ sin\frac{a}{2} =±\sqrt{\frac{1-\frac{12}{13} }{2} } = ± \frac{1}{\sqrt{26} }

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Now, we are to select the value with the correct sign. It's is obvious from the above constraints that the angle a/2 lies in the III-quadrant where 'sine' has negative value, thus the required value is negative.

hope it helped!

   

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