The answer is 3x+2 over (x+2) (x-2)
<span>2x + 5 is your answer </span>
-x^2 + 4 = 2x + 1
-x^2 - 2x + 4 - 1 = 0
-x^2 - 2x + 3 = 0
(x + 3)(-x + 1)= 0
x + 3 = 0 -x + 1 = 0
x = -3 -x = -1
x = 1
so x = -3 and x = 1
Answer:
- 0.5 + 2.985i
- 1 + 2.828i
- 1.5 + 2.598i
- 2 + 2.236i
Explanation:
Complex numbers have the general form a + bi, where a is the real part and b is the imaginary part.
Since, the numbers are neither purely imaginary nor purely real a ≠ 0 and b ≠ 0.
The absolute value of a complex number is its distance to the origin (0,0), so you use Pythagorean theorem to calculate the absolute value. Calling it |C|, that is:
Then, the work consists in finding pairs (a,b) for which:
You can do it by setting any arbitrary value less than 3 to a or b and solving for the other:

I will use b =0.5, b = 1, b = 1.5, b = 2

Then, four distinct complex numbers that have an absolute value of 3 are:
- 0.5 + 2.985i
- 1 + 2.828i
- 1.5 + 2.598i
- 2 + 2.236i
Answer:
5a²+22a+8
Step-by-step explanation:
(5a+2)(a+4)
5a² + 20a + 2a + 8
5a² + 22a + 8