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Stells [14]
2 years ago
11

11. if the ph of a solution increases from 2.0 to 4.0, the h3o^ ion concentration o a decreases by a factor of 2. b. decreases b

y a factor of 100. c. increases by a factor of 3. o d. increases by a factor of 1000,
Chemistry
1 answer:
Wittaler [7]2 years ago
8 0

Option (B) is the right answer.

Hydronium ion (H_{3}O^{+}) concentration decreases by the <u>factor of 100</u>, if the pH of a solution increases from 2.0 to 4.0.

<h3>What is pH?</h3>

The hydrogen ion concentration in water is expressed by pH. Specific to aqueous solutions, pH is the <u>negative logarithm</u> of the hydrogen ion (H+) concentration (mol/L) : pH = -log_{10}[H_{3}O^{+}  ]

Acidic solutions are those with a pH under 7, and basic solutions are those with a pH over 7. At this temperature, solutions with a pH of 7 are neutral (e.g.<u> pure water</u>). The pH neutrality <u>relies on temperature, falling below 7 if the temperature rises above 25 °C</u>.

<h3>Given: </h3>

pH1( initial pH) = 2.0

pH2( initial pH) = 4.0

[H3O+] =  initial hydronium concentration

[H3O+]* = final hydronium concentration

<h3>Formula used : </h3>

pH = -log_{10}[H_{3}O^{+}]

<h3>Solution: </h3>

pH = - log_{10}[H_{3}O^{+}] \\\\= > 10^{-pH} = [H_{3}O^{+}] \\\\similarly, \\\\10^{-pH} = [H_{3}O^{+}]*\\\\ = > 10^{-4} = [H_{3}O^{+}]*\\\\Now, \frac{[H_{3}O^{+}]*}{[H_{3}O^{+}]}  = 10^{-2}

Thus , the concentration of hydronium ion decreases by 100.

To learn more about pH :

brainly.com/question/15289741

#SPJ4

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To solve this question, we'll begin by calculating the number of half-lives that has elapsed. This can be obtained as follow:

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<h3>Number of half-lives (n) =?</h3>

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Learn more: brainly.com/question/24868345

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