Answer:
Mass = 206.38 g
Explanation:
Given data:
Mass of calcium chloride = 80.0 g
Mass of silver chloride formed = ?
Solution:
Chemical equation:
CaCl₂ + 2AgNO₃ → Ca(NO₃)₂ + 2AgCl
Number of moles of CaCl₂:
Number of moles = mass/molar mass
Number of moles = 80.0 g/ 110.98 g/mol
Number of moles = 0.72 mol
Now we will compare the moles of CaCl₂ and AgCl
CaCl₂ : AgCl
1 : 2
0.72 : 2/1×0.72 = 1.44 mol
Mass of silver chloride:
Mass = number of moles × molar mass
Mass = 1.44 mol × 143.32 g/mol
Mass = 206.38 g
Speed =distance/time
speed =150km/7200s
speed =0.0208333 km/s
so your answer is 0.0208333
The chemical equation for this combustion reaction is:
<span>C8H18 + O2
--> CO2 + H2O</span>
Balancing by adding whole number coefficients:
<span>2 C8H18 + 25
O2 --> 16 CO2
+ 18 H2O</span>
Including the phases:
<span>2 C8H18 (l) + 25 O2
(g) --> 16 CO2 (g) + 18 H2O (l)</span>
<span>where g is gas and l is liquid</span>
8.3 × 106 - trust me, it's actually right. You can use the calculator to see if I'm correct. Punch in <span>8.3 × 106 = 6.6</span>
Answer:
HI (hydrogen iodide).
Explanation:
Hello,
In this case, since iodine is in group VIIA, it has seven valence electrons at its outer shell, which means that it only needs one bond to attain the octet. Moreover, since hydrogen has just one electron at its outer shell, one hydrogen turns out enough to obey the octet when hydrogen and iodine bond as shown below:
Therefore, the required formula is:
Which is hydrogen iodide.
Best regards.
