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3 years ago

How can an experiment support or fail support a hypothesis

1 answer:

3 0

If a hypothesis is stated and outcome of the experiment is what was predicted, then it supports the hypothesis. if the experiment does not support the hypothesis, then the outcome was not what was predicted.

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If you burn 22.4 22.4 g of hydrogen and produce 2.00 × 10 2 2.00×102 g of water, how much oxygen reacted?

Mnenie [13.5K]

Answer:

179.2g of O2

Explanation:

Fir, we must obtain a balanced equation for the reaction.

The equation for the reaction is:

2H2 + 02 —> 2H2O

Next, we find the molar mass of H2 and O2 as shown below:

Molar Mass of H2 = 2x1 = 2g/mol

Mass conc. of H2 from the balanced equation = 2 x 2 = 4g

Molar Mass of O2 =16x2 = 32g/mol

From the equation,

4g of H2 required 32g of O2,

Therefore 22.4g of H2 will require = (22.4x32)/4 = 179.2g of O2

3 0

3 years ago

When a car goes around a curve at a constant speed, in which direction is it accelerating

Leno4ka [110]

C. Outside the curve

6 0

3 years ago

Help please! I’ll give brainliest!

Neporo4naja [7]

32 h this is because this problem

8 0

3 years ago

The surface area of an object to be gold plated is 49.8 cm2 and the density of gold is 19.3 g/cm-3. A current of 3.15. A is appl

garik1379 [7]

Answer: Time required to deposit an even layer of gold with given thickness is $5.3 \times 10^{2}$ sec.

Explanation:

The given data is as follows.

Surface area = 49.8 $cm^{2}$ ,

Density of gold = 19.3 $g/cm^{3}$ ,

Current = 3.15 A, thickness of gold layer = $1.2 \times 10^{-3} cm$

It is known that relation between volume, area and thickness is as follows.

V = Surface area × Thickness

= $49.8 \times 1.2 \times 10^{-3} cm$

= 0.05988 $cm^{3}$

Therefore, we will calculate the time required to deposit an even layer of gold with given thickness is calculated as follows.

$0.05988 \times cm^{3} \times \frac{19.3 g Au}{1 cm^{3}} \times \frac{1 mol Au}{197 g Au} \times \frac{3 mol e^{-}}{1 mol Au} \times \frac{96485}{1 mol e^{-}} \times \frac{1 As}{1 C} \times \frac{1}{3.20 A}$

= $5.3 \times 10^{2}$ sec

Thus, we can conclude that time required to deposit an even layer of gold with given thickness is $5.3 \times 10^{2}$ sec.

4 0

3 years ago

Please only do the ones I didn't do I will give brainiest

Xelga [282]

Answer:

1. conduction 5. heat from the air is absorbed by ice cubes is conduction 6. a hot horseshoe transfers heat to the tongs is conduction. 8. a bowl of oatmeal cools is convection 9. water is warmed over a fire is convection/radiation 10. a spoon gets warmer after sitting in a bowl of soup is conduction.

Explanation:

the last two i don't know sorry but i give u the answers to the others:)

7 0

3 years ago