Given the confidence level, sample size and sample proportion, the margin of error is approximately 8.03%.
<h3>What is the margin of error?</h3>
Margin of error is expressed mathematically as;
MOE = z × √[ (p(1-p))/n ]
Where z is z-score, p is sample proportion, n is sample size.
Given the data in the question;
- Sample size n = 125
- Sample proportion p = 0.3
- At 95% confidence, z-score = 1.960
- MOE = ?
Plug these values into the equation above.
MOE = z × √[ (p(1-p))/n ]
MOE = 1.960 × √[ (0.3( 1-0.3 ))/125 ]
MOE = 1.960 × √[ (0.3( 0.7 ))/125 ]
MOE = 1.960 × √[ (0.21)/125 ]
MOE = 1.960 × √[ 0.00168 ]
MOE = 1.960 × 0.0409878
MOE = 0.0803
MOE = 0.0803 × 100%
MOE = 8.03%
Given the confidence level, sample size and sample proportion, the margin of error is approximately 8.03%.
Learn more about margin of error here: brainly.com/question/10501147
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