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3 years ago

Ricardo is 3 years older than Courtney. In 5 years the sum of their ages will be 81. How old is Ricardo now?

Mathematics

1 answer:

kondaur [170]3 years ago

8 0

Ricardo will be cool is how and he is smart

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Sarah is 50 years old. she is twice as old as her friend bill and bill is 5 times as old as his sister jane. jane's mom is 12 ti

Pavlova-9 [17]

10 years. Bill is 25, his sister is 5, and their mother is 60.

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3 years ago

Read 2 more answers

Which expression is equivalent to (4g3h2k4)3

RSB [31]

Answer:

d) $8g^{6}h^{4} k^{12} - (h^{25} k^{15} )$

$\frac{(4g^{3} h^{2}k^{4} )^{3} }{8g^{3}h^{2} } - (h^{5} k^{3} )^{5}$ $= 8g^{6}h^{4} k^{12} - (h^{25} k^{15} )$

Step-by-step explanation:

<u><em>Explanation</em></u>

Given expression

= $\frac{(4g^{3} h^{2}k^{4} )^{3} }{8g^{3}h^{2} } - (h^{5} k^{3} )^{5}$

By using

(ab)ⁿ = aⁿbⁿ

$\frac{a^{m} }{a^{n} } = a^{m-n}$

= $\frac{(4)^{3} g^{9} h^{6}k^{12} ) }{8g^{3}h^{2} } - (h^{5} k^{3} )^{5}$

After simplification , we get

$= 8g^{9}g^{-3} h^{6} h^{-2} k^{12} - (h^{5} k^{3} )^{5}$

$= 8g^{9-3}h^{6-2} k^{12} - (h^{5} k^{3} )^{5}$

$= 8g^{6}h^{4} k^{12} - (h^{25} k^{15} )$

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2 years ago

Ray industries bought a touchscreen monitor for $1200 it is expected to depreciate at a rate of 25% per year what was the value

max2010maxim [7]

So for this problem, we will be using the exponential equation format, which is y = ab^x. The a variable is the initial value, and the b variable is the growth/decay.

Since our touchscreen starts off at a value of 1200, that will be our a variable.

Since the touchscreen is decaying in value by 25%, subtract 0.25 (25% in decimal form) from 1 to get 0.75. 0.75 is going to be your b variable.

In this case, time is our independent variable. Since we want to know the value 3 years from now, 3 is the x variable.

Using our info above, we can solve for y, which is the cost after x years.

$y=1200*0.75^3\\y=506$

In context, after 3 years the touchscreen will only be worth $506.

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3 years ago

Lexi needs 144 beads. A large box holds 100 beads. A medium box holds 10 beads. A small box holds 1 bead. Lexi already had 1 lar

ohaa [14]

She has 144-100=44. 44-4=40. Medium holds to beads you will need 4 medium boxes.

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2 years ago

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A clerk at Agency Y has determined that at speeds of 25 pages per minute it is typical for 3 out of every 100 pages she photocop

nalin [4]

Answer:

180 pages

Step-by-step explanation:

Since her photocopy session is 25 pages per minute, the total number of pages photocopied in 4 hour session can be calculated as;

number of pages = time × speed

= (4 × 60) × 25

= 240 ×25

= 6000 pages

Thus, number of pages photocopied in 4 hours is 6000.

For every 100 pages, 3 would contain some type of printing error. The number of pages she expect with printing error during 4 hour session can be determined as;

= $\frac{6000}{100}$ × 3

= 60 × 3

= 180 pages

The expected number of pages with printing error during 4 hour photocopying session is 180 pages.

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2 years ago