Typically if it is a linear function then it doesn't matter. However if it is a quadratic, cubic, and so on and so forth....(
) you may want to used the distance formula if you are not given any other points (with the exception of the vertex, asymptote or roots... etc).
Answer:
2,000
4,000
7,000
put points on (2, 2,000) - (4, 4,000) - and (7, 7,000)
Step-by-step explanation:
Since g(2) has an x value of 2, plug in 2 for x. Do 2(2)squared-2(2). That would be 4
Distance = rate*time
convert minutes to hour first because the question talking about 15 mile per hour
40 mins = 40/60 2/3 hrs
30 mins = 30/60 = 1/2hrs
Assume that s be the speed when Fritz driving, so
s + 15 will be the speed of the train.
We know the time we know the speed, Next
distance that Fritz drive =
distance the train travel =
The question: Assume that the train travels the same distance as the car
==>
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==>
==>
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Now we know that Fritz drive at 45 mph,
distance =
Answer:
<h3>31</h3>
Step-by-step explanation:
<h3>Let the other part be x.</h3>
<h3>Now,</h3><h3 /><h3>24:x=3:4</h3>
<h3>3x=96</h3><h3 /><h3>X = 96/3 = 32</h3>
<h3>1</h3>
<h3>Other part = 32</h3>
<h2>mark me brainlist!</h2>
