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FromTheMoon [43]
2 years ago
13

Frogs have been breeding like flies at the Enormous State University (ESU) campus! Each year, the pledge class of the Epsilon De

lta fraternity is instructed to tag all the frogs residing on the ESU campus. Two years ago (t = 0) they managed to tag all 42,000 of them (with little Epsilon Delta Fraternity tags). This year's pledge class discovered that all the tags had all fallen off, and they wound up tagging a total of 54,600 frogs.
Function: 42000 (1.3^t/2)
Assuming exponential population growth, and that all this year's tags have fallen off, how many tags should Epsilon Delta order for next year?
Mathematics
1 answer:
GuDViN [60]2 years ago
7 0
This year is yer number 2 , so t = 2
which means that the next year will be t = 3

So, Epsilon-delta should order :
42000 (1.3 ^ (3/2)) 
= 62,254 Tags

Hope this helps
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For this case we have that by definition, the equation of a line of the slope-intersection form is given by:

y = mx + b

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We have two points through which the line passes, so we can find the slope:

(x_ {1}, y_ {1}) :( 4, -4)\\(x_ {2}, y_ {2}) :( 8, -10)\\m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}} = \frac {-10 - (- 4)} {8-4} = \frac {-10+ 4} {4} = \frac {-6} {4} = - \frac {3} {2}

Thus, the equation is of the form:

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We substitute one of the points and find "b":

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y = - \frac {3} {2} +2

ANswer:

y = - \frac {3} {2} +2

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