Answer:
X5, m d5£t4#it8#k,osp5*9y6£, you_, I_, I &, I 5"I 5"6'7'6”7'6'6"6"I 5*95*95*59*I 5,5*5*I 5*I 5•5the area of a trapezium is 240 con 2 97 the parallel side is gucm and 26 cm long Feng
the distance between them.the area of a trapezium is 240 con 2 97 the parallel side is gucm and 26 cm long Feng
the distance between them.the area of a trapezium is 240 con 2 97 the parallel side is gucm and 26 cm long Feng
the distance between them.the area of a trapezium is 240 con 2 97 the parallel side is gucm and 26 cm long Feng
the distance between them.the area of a trapezium is 240 con 2 97 the parallel side is gucm and 26 cm long Feng
the distance between them.the area of a trapezium is 240 con 2 97 the parallel side is gucm and 26 cm long Feng
the distance between them.the area of a trapezium is 240 con 2 97 the parallel side is gucm and 26 cm long Feng
the distance between them.the area of a trapezium is 240 con 2 97 the parallel side is gucm and 26 cm long Feng
the distance between them.the area of a trapezium is 240 con 2 97 the parallel side is gucm and 26 cm long Feng
the distance between them.the area of a trapezium is 240 con 2 97 the parallel side is gucm and 26 cm long Feng
the distance between them.the area of a trapezium is 240 con 2 97 the parallel side is gucm and 26 cm long Feng
the distance between them.the area of a trapezium is 240 con 2 97 the parallel side is gucm and 26 cm long Feng
the distance between them.
I'm going to separate this into sections so it makes more sense for you to read. For the problems with π where you have to round, ask your teacher where to round, unless your textbook specifies it:
A – 100 cm^2
To calculate area of squares, you multiply l • w. It's a square, so all sides are equal, and since we know that one side = 10 cm, the area is 10 • 10 = 100
B – πr^2 (not sure if the r shows up very well, so I'm retyping it in words - pi • radius squared)
C – 25π cm^2 or an approximate round like 78.54 cm^2 (ask your teacher about this – it could be to the nearest tenth, hundredth, etc.)
To find the area of a circle, you must follow the formula πr^2. In this case, the diameter is 10. The radius is half the diameter, so to substitute the values you must find 10 ÷ 2 = 5. So the radius is 5 cm. From there you can substitute r for 5, ending up with π • 5^2. 5^2 = 25, so the area is 25π, or about 78.54, depending on where the question wants you to round.
D – An approximate round (to the nearest hundredth it is 21.46 cm^2)
To find the area of the shaded region, just subtract the circle's area from the square's area, or 100 – 25π ≈ 21.46. Again, though, ask your teacher about where to round, unless your textbook specifies it.
E – dπ (diameter • pi)
F – 10π cm^2 or an approximate round like 31.42 cm^2
The diameter is 10. 10π ≈ 31.42
Hope this helps!
-4(-4) = positive 16
Positive 16(-4) = -64
-64 is your answer
