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OLEGan [10]
3 years ago
7

Yoshi and Rana serve muffins. There are 3 muffins with nuts. 1/6 of the muffins have nuts. How many muffins do they serve in all

? how many muffins will be without nuts
Mathematics
2 answers:
Solnce55 [7]3 years ago
6 0
Total amount of muffins: 3×6= 18 muffins.

Amount of muffins without nuts:
total amount of muffins - muffins with nuts
18-3= 15 muffins without nuts

sertanlavr [38]3 years ago
4 0
Your answer to the problem is 18 muffins in all and 15 muffins without nuts.
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Step-by-step explanation:

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3 years ago
In a recent test, you scored 1.0 standard deviations above the average score attained, and the scores are normally distributed.
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97.75 %

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3 0
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Select all the pairs of equivalent expressions.
iren2701 [21]

Answer:

\huge\boxed{(3^4)^4=3^8\cdot3^8}\\\boxed{4^3\cdot5^3=20^3}\\\boxed{(4^3)^3=4^3\cdot4^3\cdo4^3}

Step-by-step explanation:

a^n\cdot a^n=a^{n+m}\\\\(a^n)^m=a^{n\cdot m}\\\\(a\cdot b)^n=a^n\cdot b^n\\=====================

(4^3)^3=4^{3\cdot3}=4^9\\4^3\cdot4^3=4^{3+3}=4^6\\\\4^9\neq4^6\to(4^3)^3\neq4^3\cdot4^3\\==================

(3^4)^4=3^{4\cdot4}=3^{16}\\3^8\cdot3^8=3^{8+8}=3^{16}\\\\(3^4)^4=3^8\cdot3^8\\================

6^4\cdot3^4=(6\cdot3)^4=18^4\\\\18^4\neq18^8\to6^4\cdot3^4\neq18^8\\=================

4^3\cdot5^3=(4\cdot5)^3=20^3\\\\4^3\cdot5^3=20^3\\=================

(4^3)^3=4^{3\cdot3}=4^9\\4^3\cdot4^3\cdot4^3=4^{3+3+3}=4^9\\\\(4^3)^3=4^3\cdot4^3\cdot4^3

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3 years ago
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