To get the square root of imperfect square we can use the formula , which is usually accurate to about two decimal places,
√X =√S +(X-S)2√S
Where, X = the number you want the square roof of, and S is the closest square you know to x.
For example 75 is an imperfect square
Thus, X=75 and thus the nearest number S = 81, this ,means √81 =9.
Putting this into the formula;
√75= 9+(75-81)/2/2(9)
= 9 + -6/18
= 9-0.33333 = 8.667
= 8.667, thus the square root of 75 is 8.66
Answer:
B is the answer.
Since 7 and 12 are both the legs of the right triangle, we are going to use pythagorean theorem.

Isolate side c

Answer:
30 - 18 + 24 ÷ 4 = 18
Step-by-step explanation:
The order of operations is
Parentheses
Exponents
Multiplication
Division
Addition
Subtraction
Use this word PEMDAS to remember the order of operation
Let us solve the problem
30 18 24 4 = 18
∵ 30 - 18 = 12
∵ 24 ÷ 4 = 6
∵ 12 + 6 = 18
That means put (-) between 30 and 18, (÷) between 24 and 4, then put (+) between 18 and 24
∴ 30 - 18 + 24 ÷ 4
- The first operation is the division
∵ 24 ÷ 4 = 6
∴ 30 - 18 + 6
- Start with 30 - 18 because in addition and subtraction we start
with who come first
∵ 30 - 18 = 12
∴ 12 + 6
- Finally add them
∵ 12 + 6 = 18
∴ 30 - 18 + 24 ÷ 4 = 18
Answer:
(u o w) (7) = 22
(w o u) 7) = 8
Step-by-step explanation:
We are given:

We need to find:
a) (u o w) (7)
First we will find (u o w) (x) and then we will find (u o w) (7)
We know that (u o w) (x) = u(w(x))
Put value of w(x) into u(x)
we have:

Now finding (u o w) (7)
We know that: (u o w) (7) = u(w(7))

So, (u o w) (7) = 22
b) (w o u) (7)
First we will find (w o u) (x) and then we will find (w o u) (7)
We know that (w o u) (x) = w(u(x))
Put value of u(x) into w(x)
we have:

Now finding (w o u) (7)
We know that (w o u) (7) = w(u(7))

So, (w o u) (7) = 8