1) -2q-5= -11 2)3(8+k) = 33 3)4/6=x/9 4)6(y+3)=24 5)4k+8=26 6)8y=6+2y 7)3x-7=20 pls help!!!!!!!!!
2 answers:
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Lagrangian:
where the function we want to minimize is actually
, but it's easy to see that 
and 
have critical points at the same vector 
.
Derivatives of the Lagrangian set equal to zero:
Substituting the first three equations into the fourth gives
Solving for
, we get a single critical point at 
, which in turn gives the least distance between the plane and (0, 2, 5) of 
.
where the function we want to minimize is actually
Derivatives of the Lagrangian set equal to zero:
Substituting the first three equations into the fourth gives
Solving for