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kow [346]
3 years ago
7

1) -2q-5= -11 2)3(8+k) = 33 3)4/6=x/9 4)6(y+3)=24 5)4k+8=26 6)8y=6+2y 7)3x-7=20 pls help!!!!!!!!!

Mathematics
2 answers:
notsponge [240]3 years ago
8 0

Answer: See below attachment

KATRIN_1 [288]3 years ago
3 0

Answer:

1) -2q-5= -11

-2q = -11+5

q = -6/-2 =3

2) 3(8+k) = 33

24 + 3k = 33

3k = 33-24

K = 9/3 = 3

3) 4/6=x/9

By cross multiplication

4x9 = Xx6

36 = 6x

So, x = 6

4) 6(y+3)=24

6y + 18 = 24

y = (24-18)/6 = 1

5)4k+8=26

4k = 26-8

k = 18/4 = 4.50

6)8y=6+2y

8y - 2y = 6

6y = 6

So, y = 1

7)3x-7=20

3x = 20+7

x = 27/3 = 9

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3 years ago
HELP COLLEGE ALGEBRA
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Answer:

1) \frac{-8}{11}  

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3) \frac{3}{4}

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Step-by-step explanation:

The slope formula of the line that pass across two points P1(x1,y1) and P2(x2,y2) is:

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You can use this formula to solve all the four points:

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\frac{6- -2}{-9 - 2} = \frac{-8}{11}

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\frac{- 9.1 - 0.6}{-9.5 - - 1.9} = \frac{97}{76} =(Rounded)= 1.276

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\frac{2-5}{-2 -2} = \frac{3}{4}

4)

\frac{4-4}{-9 --4} = \frac{0}{-5} = 0 \\\\

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3 years ago
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