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3 years ago

Thanks for your help

Mathematics

1 answer:

vampirchik [111]3 years ago

5 0

The answer would be b=4.2

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Lewis checked the balance of his savings

vichka [17]

Answer:

Linear

Step-by-step explanation:

The balances each go up by $110

300 + 110 = 410

410 + 110 = 520

520 + 110 = 630

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3 years ago

Multiply the binomial and the trinomial. <br> (x-2)(x^2+2x+4)

malfutka [58]

Answer:

Step-by-step explanation:

To solve this problem, we need to multiple $x$ and -2 by $x^{2} + 2x + 4$ and add the results together:

$x(x^{2} + 2x + 4)$

$x^{3} + 2x^{2} + 4x$

$-2(x^{2} + 2x + 4)$

$-2x^{2} - 4x - 8$

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$(x^{3} + 2x^{2} + 4x) + (-2x^{2} - 4x - 8)$

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3 years ago

Will a geometric figure and its rotated image always,sometimes,or never have to same perimeter?

mash [69]

They will have the same Perimeter, unless you shrink or grow the image then nothing with change

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3 years ago

If 588 digits were used to number the pages of a book, how many pages are in this book?

andre [41]

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Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Find a formula for the described function. A rectangle has perimeter 16 m. Express the area A of the rectangle as a function of

Alex17521 [72]

Part A:

Let the length of one of the sides of the rectangle be L, then the length of the other side is obtained as follow.

Let the length of the other side be x, then

$2(L+x)=16 \\ \\ \Rightarrow L+x=8 \\ \\ \Rightarrow x=8-L$

Thus, if the length of one of the side is x, the length of the other side is 8 - L.

Hence, the area of the rectangle in terms of L is given by

$L(8 - L) = 8L-L^2$

Part B:

To find the domain of A

Recall that the domain of a function is the set of values which can be assumed by the independent variable. In this case, the domain is the set of values that L can take.

Notice that the length of a side of a rectangle cannot be negative or 0, thus L cannot be 8 as 8 - 8 = 0 or any number greater than 8.

Hence the domain of the area are the set of values between 0 and 8 not inclusive.

Therefore,

$dom(Area)=0\ \textless \ L\ \textless \ 8 \ or \ (0, 8)$

3 0

3 years ago