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exis [7]
3 years ago
7

If the state sales tax rate is 8%, how much money will you need to purchase a pair of jeans costing $29.99 and a shirt costing $

16.99?
A. $3.75
B. $3.76
C. $50.73
D. $50.74
Mathematics
2 answers:
d1i1m1o1n [39]3 years ago
7 0
29.99 + 16.99 = 46.98

46.98 + 0.08(46.98) = 46.98 + 3.76 = 50.74 <==
LekaFEV [45]3 years ago
4 0
29.99+16.99=46.98. 46.98x8%=3.75. 46.98+3.75=50.73(C)
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A common blood test performed on pregnant women to screen for chromosome abnormalities in the fetus measures the human chorionic
goldfiish [28.3K]

Answer:

(a) The proportion of women who are tested, get a negative test result is 0.82.

(b) The proportion of women who get a positive test result are actually carrying a fetus with a chromosome abnormality is 0.20.

Step-by-step explanation:

The Bayes' theorem states that the conditional probability of an event <em>E</em>_{i}, of the sample space <em>S,</em> given that another event <em>A</em> has already occurred is:

P(E_{i}|A)=\frac{P(A|E_{i})P(E_{i})}{\sum\liits^{n}_{i=1}{P(A|E_{i})P(E_{i})}}

The law of total probability states that, if events <em>E</em>₁, <em>E</em>₂, <em>E</em>₃... are parts of a sample space then for any event <em>A</em>,

P(A)=\sum\limits^{n}_{i=1}{P(A|B_{i})P(B_{i})}

Denote the events as follows:

<em>X</em> = fetus have a chromosome abnormality.

<em>Y</em> = the test is positive

The information provided is:

P(X)=0.04\\P(Y|X)=0.90\\P(Y^{c}|X^{c})=0.85

Using the above the probabilities compute the remaining values as follows:

P(X^{c})=1-P(X)=1-0.04=0.96

P(Y^{c}|X)=1-P(Y|X)=1-0.90=0.10

P(Y|X^{c})=1-P(Y^{c}|X^{c})=1-0.85=0.15

(a)

Compute the probability of women who are tested negative as follows:

Use the law of total probability:

P(Y^{c})=P(Y^{c}|X)P(X)+P(Y^{c}|X^{c})P(X^{c})

          =(0.10\times 0.04)+(0.85\times 0.96)\\=0.004+0.816\\=0.82

Thus, the proportion of women who are tested, get a negative test result is 0.82.

(b)

Compute the value of P (X|Y) as follows:

Use the Bayes' theorem:

P(X|Y)=\frac{P(Y|X)P(X)}{P(Y|X)P(X)+P(Y|X^{c})P(X^{c})}

             =\frac{(0.90\times 0.04)}{(0.90\times 0.04)+(0.15\times 0.96)}

             =0.20

Thus, the proportion of women who get a positive test result are actually carrying a fetus with a chromosome abnormality is 0.20.

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If we have 9 candy bars and each student gets 1/3 candy barwith 10 students, how much of a sandwich does each student get? Expla
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Answer:

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Step-by-step explanation:

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you know that if 15÷3=5 then 5×3=15. if you know that 7÷8=7/8, what can you conclued about the product of 7/8 and 8
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Answer:

The product = 7

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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