If its multiplication sipmlest form is, 6/10
If its addition simplest form is, 7/9
If its any other just tell me! Hope i was right :p
Answer:
Henri invested $ 4,500 in bonds and $ 19,500 in stocks.
Step-by-step explanation:
Given that Henri has $ 24000 invested in stocks and bonds, and the amount in stocks is $ 6000 more than three times the amount in bonds, to determine the amount that Henri invested in stocks (S) and the amount he invested in bonds (B), the following calculations must be performed:
6000 + 3B + B = 24000
3B + B = 24000 - 6000
4B = 18000
B = 18000/4
B = 4500
S = 6000 + 3x4500
S = 6000 + 13500
S = 19500
Thus, Henri invested $ 4,500 in bonds and $ 19,500 in stocks.
Answer:
47,759
Step-by-step explanation:
77+216 x 326 divided by 2
So find the difference between 1995 and 2022 to make it easier
2022-1995=27
so the rephrased question is
when hazel was x years old, she was 25 years older than son gary who was y old at that time (equation is x is 25 more than y or x=25+y)
in 27 years, (this means x+27 and y+27) hazel's age will be 150% of gary's age (x+27= 150% of y+27)
percent means parts out of 100 so 150%=150/100=15/10=1.5
'of' in math means multiply so
the equations are
x=25+y
x+27=1.5(y+27)
subsitute 25+y for x in second euation
25+y+27=1.5(y+27)
add like terms
y+52=1.5(y+27)
I personally dislike decimals to multiply both sides by 2 to make 2 0.5's or 1 (you are technically supposed to distribute or divide both sides by 1.5) so
2y+104=3(y+27)
distribute
2y+104=3y+81
subtract 2y from both sides
104=y+81
subtract 81 from both sides
23=y
subsitute
x=25+y
x=25+23
x=48
Hazel was 48 and Gary was 23 in the year of 1995
Answer:
C. the initial number of club members, in hundreds
Step-by-step explanation:
The general form of such an expression is ...
(initial value)×(growth factor per period)^(number of periods)
The use of 12 in the exponent suggests that the growth factor of 1.02 is an annual factor. If that is the case, for t months, the membership should be modeled as ...
1.8(1.02^(t/12))
_____
As written, the expression is not an exponential expression. With appropriate parentheses, it might be a good model if t is the number of <em>years</em> (not <em>months</em>), and if the expected growth rate is 2% per month.
1.8(1.02^(12t))
