Question

Which equation described a line parallel to the line that connects points (-8 ,9) and (3, -4)?

Answer 1

Answer:

y = (-13/11)x - 5/11

Step-by-step explanation:

Where's the list of equations from which you're to choose?

The line that connects points (-8 ,9) and (3, -4) has the following slope:

          9 - (-4)

m = ----------------- = -13/11

          -8 - 3

Then the new line with this slope is y = (-13/11)x + c

and because (-8, 9) satisfies this equation, 9 = (-13/11)(-8) + c, and we need to calculate c from this.                                 9 = 104/11 + c, or

                                                                        -c = 104/11 - 99/11, or - 5/11

Then the desired equation is y = (-13/11)x - 5/11