- AC=Hypotenuse=20
- BC=Base=16
AB:-
Apply Pythagorean theorem





Now
- DE=AB/3=12/3=4
- EF=BC/3=16/3=5.3
- DF=AC/3=20/3=6.6
Now



The concentration of hypochlorite ion if 20.00 ml of bleach requires 32.00 ml of 0.500 m hcl to reach the equivalence point is: 0.800 M.
<h3>
Concentration of hypochlorite ion</h3>
Given:
Ca = concentration/molarity of acid=0.500 M
Va = volume of acid= 32.00 cm3
Cb = concentration/molarity of base=?
VB =volume of base= 20.00 cm3
Hence:
Concentration of hypochlorite ion=0.500 × 0 × 1/ 20.00
Concentration of hypochlorite ion=0.800M
Inconclusion the concentration of hypochlorite ion if 20.00 ml of bleach requires 32.00 ml of 0.500 m hcl to reach the equivalence point is: 0.800 M.
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Explanation:
It’s the first one i know because i took the test i hope this helps