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docker41 [41]
2 years ago
10

What is the answer to this problem ?

Mathematics
2 answers:
Dimas [21]2 years ago
8 0

Answer:

11

Step-by-step explanation:

Plug 4 into the x, 6(4) = 24

24 - 13 = 11

Kay [80]2 years ago
7 0
Your answer is 11

6*4=24
24-13=11
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Somebody can help me please I don’t understand:(
Alex17521 [72]

Answer:

1) x=67, y=83, z=80 2) x=5

Step-by-step explanation:

1) 28+85=113 a triangle is 180 degrees so 180-113=67 so x=67

x and y are supplementary meaning both sides equal 150 so 150-67=83

83+17=100 now going back how much did i say a triangle should equal? 180 so z is 80

2)a triangle = 180 since the triangle is a right angle it includes the angle 90 so make the equation to solve for x

180=90+8x+2+9x+3

take 90 to other side so you are subtracting 180-90

90=8x+2+9x+3

combine like terms

90=17x+5

subtrcat 5 from 90

85=17x

now divide 85 by 17 and you get x=5

8 0
3 years ago
To factor 9x^2-4 you can first rewrite the expression as
jekas [21]

Answer: You rewrite in factor form which for this is (3x+2)(3x-2).

Step-by-step explanation:

5 0
4 years ago
Read 2 more answers
Use the drop-down menus to identify the values of the
tia_tia [17]

Answer:

Vertex= (0,4)

Domain= x: all real number

Range: ( - ∞, 4] or y ≤ 4

<u>OAmalOHopeO</u>

6 0
3 years ago
There are 16 kids on a soccer team. The players are either boys or girls, and they either prefer playing offense or defense. The
Mariana [72]

Answer:

P(B|A)=\frac{2}{7}

Step-by-step explanation:

The probability of P(B|A) can be read as the probability of event B occurring given event A. In this question, event A occurs when the chosen player is a girl. There are 7 girls on the soccer team. Event B occurs when the chose player plays defense. Since P(B|A) stipulates that event A already occurred, we want the probability of choosing a player who prefers defense from the 7 girls. There are 2 girls who prefer defense, hence P(B|A)=\boxed{\frac{2}{7}}.

<u>Alternative:</u>

For dependent events A and B, the conditional probability of event B occurring given A is given by:

P(B|A)=P(B\cap A)\div P(A)

P(B\cap A) indicates the intersection of P(B) and P(A). In this case, it is the probability that both events occur. Since there are 16 kids on the soccer team and only 2 are girls and prefer defense, P(B\cap A)=\frac{2}{16}=\frac{1}{8}. The probability of event A occurring (chosen player is a girl) is equal to the number of girls (7) divided by the number of kids on the team (16), hence P(A)=\frac{7}{16}.

Therefore, the probability of event B occurring, given event A occurred, is equal to:

P(B|A)=\frac{1}{8}\div \frac{7}{16},\\\\P(B|A)=\frac{1}{8}\cdot \frac{16}{7}=\boxed{\frac{2}{7}}

5 0
3 years ago
Solve using substitution.<br> Y = -x + 1<br> y = -2x + 8
sergey [27]
To find x- intercept the zero so substitute y=0
0=-x+1
X=1 thqt should be your answer
Hope this helped
Answer: x=1
3 0
3 years ago
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