4.2 is the answer of this question you are asking ✌️
Answer:
0
Step-by-step explanation:
125×^6_81=0
×^6 we do not support this expression
ans = 0
Answer:
The ratio of the intensities is roughly 6:1.
Step-by-step explanation:
The intensity I() of an earthquake wave is given by:
<em>where P: is the power ans d: is the distance. </em>
Hence, the ratio of the intensities of an earthquake wave passing through the Earth and detected at two points 19 km and 46 km from the source is:
<em>where I₁ = P/4πd₁², d₁=19 km, I₁ = P/4πd₂² and d₂=46 km </em>
Therefore, the ratio of the intensities is roughly 6:1.
I hope it helps you!
Answer:
1. x = 2√3 or 3.46
2. y = 4√3 or 6.93
3. z = 4√6 or 9.80
Step-by-step explanation:
1. Determination of the value of x.
Angle (θ) = 60°
Opposite = 6
Adjacent = x
Tan θ = Opposite /Adjacent
Tan 60 = 6 / x
√3 = 6/x
Cross multiply
x√3 = 6
Divide both side by √3
x = 6 / √3
Rationalise
x = (6 / √3) × (√3/√3)
x = 6√3 / 3
x = 2√3 or 3.46
2. Determination of the value of y.
Angle (θ) = 60°
Opposite = 6
Hypothenus = y
Sine θ = Opposite /Hypothenus
Sine 60 = 6/y
√3/2 = 6/y
Cross multiply
y√3 = 2 × 6
y√3 = 12
Divide both side by √3
y = 12/√3
Rationalise
y = (12 / √3) × (√3/√3)
y = 12√3 / 3
y = 4√3 or 6.93
3. Determination of the value of z.
Angle (θ) = 45°
Opposite = y = 4√3
Hypothenus = z
Sine θ = Opposite /Hypothenus
Sine 45 = 4√3 / z
1/√2 = 4√3 / z
Cross multiply
z = √2 × 4√3
z = 4√6 or 9.80
Be more descriptive of the problem
