Answer:
6y^3x^3-y^2x^3
Step-by-step explanation:
This is a working backwards problem. You know he has $35 at the end. Before he gave his brother $5, he would have $40, which is half of what he had before he bought the clothes, so he would have had $80. Before he spent the $40 on shoes, he would have had $120, so the answer is $120.
Alright, since there are 5 numbers, and the mean (or average) is (sum)/(amount of numbers), we have (sum)/5=14. Multiplying both sides by 5, we have the sum being 80. The median of 10 means that in a, b, c, d, e, 10 has to be c and the numbers have to be in ascending order. A and b must be 10 or lower, while d and e must be 10 or higher. Putting some random numbers in, we can have 1, 1, 10, 15, and e. We left e there because the sum needs to be 80, and since 1+1+10+15=27, 80-27=53=e. This, however, would not work if e was less than 10 and we therefore would have needed to make some numbers lower to compensate for this. Our answer is therefore 1, 1, 10, 15, 53
Answer:
(x/4) +1 OR (4/x)+1
Step-by-step explanation:
3*3+4*4=x*x and 9+16=25 so x is 5 and then add other sides so 5+8+4+5
