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2 years ago

What additional information is needed to prove

Mathematics

2 answers:

icang [17]2 years ago

8 0

Answer:

Choice B.

Step-by-step explanation:

BC ≅ FE.

You need 2 sides and the included angle to be congruent.

statuscvo [17]2 years ago

4 0

Answer:

i think its b

Step-by-step explanation:

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Which of the following relations is a function?

trasher [3.6K]

Answer:

a{(1, 3), (2, 3), (4,3), (9,3)}

Step-by-step explanation:

For the relation to be a function, each x can only go to 1 y

a{(1, 3), (2, 3), (4,3), (9,3)}

function

b{(1, 2), (1, 3), (1, 4), (1,5)}

x=1 goes to 4 different y's so not a function

c{(5, 4), (-6, 5), (4, 5), (4, 0)}

x=4 goes to 2 different y's so not a function

d{(6,-1), (1,4), (2, 3), (6, 1)}

x = 6 goes to 2 different y's so not a function

5 0

3 years ago

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6 - 8x = 6x - 9x + 11

mars1129 [50]

6-8x=-3x+11

-8x+3x=11-6

-5x=5

x=-1

The first step is to isolate the variable, then you solve. Hope this helps, brainliest if you can.

6 0

2 years ago

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Find sin(a)&cos(B), tan(a)&cot(B), and sec(a)&csc(B).

Reil [10]

Answer:

Part A) $sin(\alpha)=\frac{4}{7},\ cos(\beta)=\frac{4}{7}$

Part B) $tan(\alpha)=\frac{4}{\sqrt{33}},\ tan(\beta)=\frac{4}{\sqrt{33}}$

Part C) $sec(\alpha)=\frac{7}{\sqrt{33}},\ csc(\beta)=\frac{7}{\sqrt{33}}$

Step-by-step explanation:

Part A) Find $sin(\alpha)\ and\ cos(\beta)$

we know that

If two angles are complementary, then the value of sine of one angle is equal to the cosine of the other angle

In this problem

$\alpha+\beta=90^o$ ---> by complementary angles

$sin(\alpha)=cos(\beta)$

Find the value of $sin(\alpha)$ in the right triangle of the figure

$sin(\alpha)=\frac{8}{14}$ ---> opposite side divided by the hypotenuse

simplify

$sin(\alpha)=\frac{4}{7}$

therefore

$sin(\alpha)=\frac{4}{7}$

$cos(\beta)=\frac{4}{7}$

Part B) Find $tan(\alpha)\ and\ cot(\beta)$

we know that

If two angles are complementary, then the value of tangent of one angle is equal to the cotangent of the other angle

In this problem

$\alpha+\beta=90^o$ ---> by complementary angles

$tan(\alpha)=cot(\beta)$

<em>Find the value of the length side adjacent to the angle alpha</em>

Applying the Pythagorean Theorem

Let

x ----> length side adjacent to angle alpha

$14^2=x^2+8^2\\x^2=14^2-8^2\\x^2=132$

$x=\sqrt{132}\ units$

simplify

$x=2\sqrt{33}\ units$

Find the value of $tan(\alpha)$ in the right triangle of the figure

$tan(\alpha)=\frac{8}{2\sqrt{33}}$ ---> opposite side divided by the adjacent side angle alpha

simplify

$tan(\alpha)=\frac{4}{\sqrt{33}}$

therefore

$tan(\alpha)=\frac{4}{\sqrt{33}}$

$tan(\beta)=\frac{4}{\sqrt{33}}$

Part C) Find $sec(\alpha)\ and\ csc(\beta)$

we know that

If two angles are complementary, then the value of secant of one angle is equal to the cosecant of the other angle

In this problem

$\alpha+\beta=90^o$ ---> by complementary angles

$sec(\alpha)=csc(\beta)$

Find the value of $sec(\alpha)$ in the right triangle of the figure

$sec(\alpha)=\frac{1}{cos(\alpha)}$

Find the value of $cos(\alpha)$

$cos(\alpha)=\frac{2\sqrt{33}}{14}$ ---> adjacent side divided by the hypotenuse

simplify

$cos(\alpha)=\frac{\sqrt{33}}{7}$

therefore

$sec(\alpha)=\frac{7}{\sqrt{33}}$

$csc(\beta)=\frac{7}{\sqrt{33}}$

6 0

3 years ago

Solve by graphing y<7/3x + 5 and x<-3

Molodets [167]

Slope : -7/3

Y-Intercept: 4

4 0

3 years ago

A large container holds 8 gallons of water. It begins leaking at a constant rate. After 32 minutes, the container has 6 gallons

natta225 [31]

Answer:

I believe the answer it 0.1875

6 0

3 years ago

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