The signaling molecule for flowering might be released earlier than usual in a long-day plant exposed to flashes of

1 answer:

7 0

The signaling molecule for flowering might be released earlier than usual in a long-day plant exposed to flashes of red light during the night.

Higher plants are sessile organisms that sense and respond to environmental stimuli such as light and chemical cues by changing their morphology.

The signaling pathway uses a complex network of interactions to coordinate biochemical and physiological responses such as flowering, fruit ripening, germination, photosynthetic regulation, and shoot or root development.

These signals are first recognized by receptors and transmitted through complex networks to the cell nucleus.

The signal is transduced to the nucleus by one of several systems involving GTP-binding proteins (G proteins) that change activity upon GTP binding, a protein kinase cascade that sequentially phosphorylates and activates various proteins and Membrane ion channels that alter the ionic properties of cells.

This signal is manifested in the nucleus as a change in the activity of DNA-binding proteins, transcription factors that specifically interact with and regulate the regulatory regions of genes.

Thus, detection of environmental signals is transmitted through transduction pathways, and changes in transcription factor activity can coordinate expression changes in gene portfolios to guide new developmental programs.

Learn more about signaling here : brainly.com/question/9381928

#SPJ4

You might be interested in

A biochemist isolates and purifies various molecules needed for DNA replication. When she adds these molecules to DNA, replicati

olga55 [171]

Answer:

DNA ligase

Explanation:

The biochemist must have left out DNA ligase enzyme.

The DNA ligase enzyme is able to catalyze the formation of phosphodiester bonds and as such, capable of joining strands of DNA together to form a single strand.

The numerous DNA segments of a few nucleotides long observed by the biochemist must have been the replicated product of the lagging DNA strand. The lagging strand is replicated discontinuously in short strands because the DNA polymerase enzyme can only elongate primers in 5' to 3' direction. The short segments are known as Okazaki segments and are usually joined together to form a whole strand by the DNA ligase enzyme.

Hence, the missing component is the DNA ligase.

3 0

2 years ago

Which one is it?? It’s on usatestprep.

sweet-ann [11.9K]

The other guy is right, B is the answer now hurry and get that test prep done

8 0

2 years ago

Which of these advantages to social media as a new media, could also be viewed as a disadvantage

andriy [413]

The disadvantage of having imformation at your fingertips is that not all of information could be true but only mere ideas or theories and that having alot of information can be overwhelming to the point where you can process so much information you might forget about the important things you come across for some propaganda trying to get your attention

7 0

2 years ago

Read 2 more answers

What would happen if there was a sudden increase in the amount of greenhouse gases in Earth's atmosphere

Harrizon [31]

There would be a much more severe cause of global warming if there is a sudden increase in greenhouses gases. With greenhouse gasses such as carbon dioxide, the heat of the earth cannot be penetrated through the atmosphere and will be trapped, the sunlight also cannot be reflected.

3 0

2 years ago

When a germ cell undergoes meiosis, which event would MOST likely result in four aneuploid daughter

sveta [45]

Answer:

B. misalignment of the chromosomes during anaphase I

Explanation:

Aneuploidy refers to an error in the chromosomal number of a cell. This occurs when the chromosomes fail to separate equally into individual cells, a process called MEIOTIC NONDISJUNCTION. Meiotic disjunction can occur in either the anaphase stage of meiosis I or meiosis II, however, different outcomes are produced.

When chromosomes fail to separate at meiosis I, it results in two gametes that lack that particular chromosome (n-1) and two gametes with two copies of the chromosome (n+1). This means that the four daughter cells will have an incorrect number of chromosomes, hence, the misalignment of the chromosomes during anaphase I will result in four aneuploid daughter cells.

6 0

2 years ago