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Sergeeva-Olga [200]
2 years ago
5

Help, very important hw!!!

Mathematics
1 answer:
kvv77 [185]2 years ago
8 0

The stem-and-leaf plot for the distribution is given as follows:

  • 1| 9
  • 2| 2 2 3 5 7 7 8 8
  • 3| 0 1 1 2 3 3 4 5 5 5 7 8 9
  • 4| 0 0 1 3

b) From the plot, the correct options are given as follows:

  • A typical content is 32 calories per 100 ml.
  • The distribution is roughly symmetric.

<h3>What is a stem-and-leaf plot?</h3>

The stem-and-leaf plot lists all the measures in a data-set, with the first number as the key, for example:

4|5 = 45.

For this problem, the observations are given at the top in red, and using each <u>first digit as the key</u>, the stem and leaf plot is:

  • 1| 9
  • 2| 2 2 3 5 7 7 8 8
  • 3| 0 1 1 2 3 3 4 5 5 5 7 8 9
  • 4| 0 0 1 3

The mean of these observations is:

(19 + 2 x 22 + 23 + 25 + 2 x 27 + 2 x 28 + 30 + 2 x 31 + 32 + 2 x 33 + 34 + 3 x 35 + 37 + 38 + 39 + 2 x 40 + 41 + 43)/26 = 32(approximately)

The correct statements from the plot are as follows:

  • A typical content is 32 calories per 100 ml(due to the mean).
  • The distribution is roughly symmetric(13 values below the mean, 13 at or above).

More can be learned about stem-and-leaf plots at brainly.com/question/28015028

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23) A movie theatre has 900 seats of which 15% are in the balcony. How many seats are NOT in the balcony?
just olya [345]

Answer:

A.765 seats are not in the balcony

Step-by-step explanation:

if 15% are in the balcony then 85% are not in the balcony so..

900 * 0.85 = 765

4 0
2 years ago
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What is the value of 4y+2y-8 if y=0.5
RUDIKE [14]

Answer:

-5

Step-by-step explanation:

4x0.5=2

2x0.5=1

2+1=3

3-8=-5

8 0
2 years ago
each of the 20 balls is tossed independently and at random into one of the 5 bins. let p be the probability that some bin ends u
amm1812

if p is the probability that some bin ends up with 3 balls and q is the probability that every bin ends up with 4 balls. pq is 16.

First, let us label the bins with 1,2,3,4,5.

Applying multinomial distribution with parameters  n=20  and  p1=p2=p3=p4=p5=15  we find that probability that bin1 ends up with 3, bin2 with 5 and bin3, bin4 and bin5 with 4 balls equals:

5−2020!3!5!4!4!4!

But of course, there are more possibilities for the same division  (3,5,4,4,4)  and to get the probability that one of the bins contains 3, another 5, et cetera we must multiply with the number of quintuples that has one 3, one 5, and three 4's. This leads to the following:

p=20×5−2020!3!5!4!4!4!

In a similar way we find:

q=1×5−2020!4!4!4!4!4!

So:

pq=20×4!4!4!4!4!3!5!4!4!4!=20×45=16

thus, pq = 16.

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7 0
1 year ago
Big chickens: The weights of broilers (commercially raised chickens) are approximately normally distributed with mean 1387 grams
Nataliya [291]

Answer:

a) 0.2318

b) 0.2609

c) No it is not unusual for a broiler to weigh more than 1610 grams

Step-by-step explanation:

We solve using z score formula

z-score is is z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.

Mean 1387 grams and standard deviation 192 grams. Use the TI-84 Plus calculator to answer the following.

(a) What proportion of broilers weigh between 1150 and 1308 grams?

For 1150 grams

z = 1150 - 1387/192

= -1.23438

Probability value from Z-Table:

P(x = 1150) = 0.10853

For 1308 grams

z = 1308 - 1387/192

= -0.41146

Probability value from Z-Table:

P(x = 1308) = 0.34037

Proportion of broilers weigh between 1150 and 1308 grams is:

P(x = 1308) - P(x = 1150)

0.34037 - 0.10853

= 0.23184

≈ 0.2318

(b) What is the probability that a randomly selected broiler weighs more than 1510 grams?

1510 - 1387/192

= 0.64063

Probabilty value from Z-Table:

P(x<1510) = 0.73912

P(x>1510) = 1 - P(x<1510) = 0.26088

≈ 0.2609

(c) Is it unusual for a broiler to weigh more than 1610 grams?

1610- 1387/192

= 1.16146

Probability value from Z-Table:

P(x<1610) = 0.87727

P(x>1610) = 1 - P(x<1610) = 0.12273

≈ 0.1227

No it is not unusual for a broiler to weigh more than 1610 grams

8 0
3 years ago
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