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3 years ago

9

Which algebraic expression represents this phrase?

1 answer:

Westkost [7]3 years ago

5 0

The word "product" means <em>multiplication </em>

that means the answer is

40 · d

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What is the length of LINE GH?<br> And please explain why thank you:

lesya692 [45]

co-ordinates of point G are (1,2)

co-ordinates of point H are (3,-3)

so, by distance formula :

$\sqrt{( {x1 - x1})^{2} + ( {y1 - y2})^{2} } \\ = \sqrt{( {1- 3})^{2} + ( {2 - ( - 3)})^{2} } \\ \sqrt{( { - 2})^{2} + ( {2 + 3})^{2} } \\ \sqrt{( { - 2})^{2} + ( {5})^{2} } \\ \sqrt{4 + 25} \\ \sqrt{29}$

so, it is root(29) or 5.38 units

7 0

3 years ago

How much interest is earned on $210 at 8% for 2 years?<br> $3.60<br> $360<br> $410<br> $33.60

oksano4ka [1.4K]

You would earn $33.60 of interest

Explanation: To find the interest you would multiply 210 by .08 (the percent in its decimal form) by 2 to get 33.60

8 0

3 years ago

Read 2 more answers

Solve for n in the literal equation a(n-2)+5=bn

Helga [31]

Answer:

<u><em>Answer is below</em></u>

Step-by-step explanation:

<em><u>a(n-2)+5=bn</u></em>

<em><u>Add -bn to both sides</u></em>

<em><u>an-2a+5+(-bn)=bn+(-bn)</u></em>

<em><u>an-bn-2a+5=0</u></em>

<em><u>add two a to both sides</u></em>

<em><u>an−bn−2a+5+(2a)=0+(2a)</u></em>

<em><u>an−bn+5=2a</u></em>

<em><u>Add -5 to both sides</u></em>

<em><u>an−bn+5+(-5)=2a+(-5)</u></em>

<em><u>an−bn=2a−5</u></em>

<em><u>Factor out our variable</u></em>

<em><u>n(a−b)=2a−5</u></em>

<em><u>Divide both sides by a-b</u></em>

<em><u>n(a-b)/a-b=2a-5/a-b</u></em>

<em><u>n=2a-5/a-b</u></em>

<em><u>Hope this helps</u></em>

7 0

3 years ago

Please help and show work

Bogdan [553]

The answer should be X= 3.60m

3 0

3 years ago

5. Mis the midpoint of CD. C has coordinates (-1,-1) and

lana66690 [7]

Answer/Step-by-step Explanation:

4. Midpoint (M) of AB, for A(-2, -3) and B(1, 2) is given as:

$M(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2})$

Let $A(-2, -3) = (x_1, y_1)$

$B(1, 2) = (x_2, y_2)$

Thus:

$M(\frac{-2 + 1}{2}, \frac{-3 + 2}{2})$

$M(\frac{-1}{2}, \frac{-1}{2})$

5. Given M(3, 5) as midpoint of CD, and C(-1, -1),

let $C(-1, -1) = (x_2, y_2)$

$D(?, ?) = (x_1, y_1)$

$M(3, 5) = (\frac{x_1 +(-1)}{2}, \frac{y_1 +(-1)}{2})$

Rewrite the equation to find the coordinates of D

$3 = \frac{x_1 - 1}{2}$ and $5 = \frac{y_1 - 1}{2}$

Solve for each:

$3 = \frac{x_1 - 1}{2}$

$3*2 = \frac{x_1 - 1}{2}*2$

$6 = x_1 - 1$

$6 + 1= x_1 - 1 + 1$

$7 = x_1$

$x_1 = 7$

$5 = \frac{y_1 - 1}{2}$

$5*2 = \frac{y_1 - 1}{2}*2$

$10 = y_1 - 1$

$10 + 1= y_1 - 1 + 1$

$11 = y_1$

$y_1 = 11$

Coordinates of D is (7, 11)

7 0

3 years ago